Answer:
a. 
b. 
c. 
Explanation:
Hello,
a. By applying the given information, one obtains:
b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:
c. Here, the propane's combustion chemical reaction is stated:
This enthalpy of reaction is computed via:
Δ
Finally, since it is done for 20 lb of propane (), the obtainable energy is:
Best regards.
Answer:
Determining what data to collect.
Explanation:
The answer to your question is A I think
Answer:
H^+(aq) + OH^-(aq) -------> H2O(l)
Explanation:
We must first write the molecular reaction equation as follows;
HNO3(aq) + NaOH(aq) ------>NaNO3(aq) + H2O(l)
The complete ionic equation is;
H^+(aq) + NO3^-(aq) + Na^+(aq) + OH^-(aq) -------> Na^+(aq) + NO3^-(aq) + H2O(l)
The net ionic equation therefore is;
H^+(aq) + OH^-(aq) -------> H2O(l)
Answer:PH2=0.994atm, mass of zinc=0.606g
Explanation:
Equation for the reaction is written as;
Zn(s) + 2HCl(aq) - ZnCl2(aq) + H2(g)
V= 240ml = 0.240L
T= 30.8oC = 303.8K
Ptotal= 1.036atm
Pwater = 32mmHg at 30oC = 0.042atm
Therefore
PH2 = Ptotal - Pwater
= 1.036-0.042atm
=0.994atm
But PV= nRT
n = PV/RT
= 0.994x0.240/0.0821x303.8
= 0.24/24.94
=0.009324moles
For the grams of zinc
n=mass in grams/molar mass
Mass in grams = no of moles x molar mass
=0.009324x65 = 0.606g
