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Pachacha [2.7K]
4 years ago
6

How are isotopes defined?forms of different elements that have the same number of neutrons in each atomforms of different elemen

ts that have the same number of protons in each atomforms of the same element that differ in the number of neutrons in each atomforms of the same element that differ in the number of protons in each atom?
Chemistry
2 answers:
Masja [62]4 years ago
5 0

Your answer is C forms of the same element that differ in the number of neutrons in each atom because if the number of neutrons change the whole element changes.
quester [9]4 years ago
3 0

Answer: Option (c) is the correct answer.

Explanation:

When there are same number of protons but different number of neutrons in the nuclei of two or more forms of an atom then they are known as isotopes.

For example, ^{12}_{6}C and ^{13}_{6}C are isotopes.

Thus, we can conclude that out of the following options, isotopes are defined as forms of the same element that differ in the number of neutrons in each atom.

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What are the products of the complete combustion of a hydrocarbon in excess oxygen
dangina [55]
The products for the complete combustion of a hydrocarbon in excess air is carbon dioxide and water. Any hydrocarbon when reacted with oxygen will always yield the said products. Incomplete combustion, on the other hand, yields carbon monoxide and water.
4 0
4 years ago
Copper is formed when aluminum reacts with copper (II) sulfate in a single-replacement reaction. How many moles of copper can be
serg [7]

Answer:

The answer to your question is the limiting reactant is CuSO₄ and 0.975 moles of Cu were obtained

Explanation:

moles of Copper = ?

mass of Aluminum = 29 g

mass of CuSO₄ = 156 g

Limiting reactant = ?

Balanced Chemical reaction

                  3 CuSO₄   +  2 Al   ⇒   3 Cu   +  Al₂(SO₄)₃

Calculate the moles of reactants

CuSO₄ = 64 + 32 + (16 x 4) = 160g

Al = 27 g

                160 g of CuSO₄  ----------------- 1 mol

                156 g                   -----------------  x

                      x = (156 x 1) / 160

                      x = 0.975 moles

               27 g of Al -------------------------- 1 mol

               29 g of Al -------------------------- x

                x = (29 x 1)/27

                x = 1.07 moles

Calculate proportions to find the limiting reactant

Theoretical     3 moles CuSO₄/2 moles Al = 1.5 moles

Experimental  0.975 moles CuSO₄/1.07 moles = 0.91

The experimental proportion was lower than the theoretical proportion that means that the limiting reactant is CuSO₄.      

                    3 moles of CuSO₄ ------------------ 3 moles of Cu

                 0.975 moles of CuSO₄ ---------------  x

                         x = (0.975 x 3)/3

                        x = 0.975 moles of Cu were obtained.        

3 0
3 years ago
Read 2 more answers
sebanyak 36 gram glukosa (C6H12O6,M=180 g/mol) dilarutkan dalam 250 gram air.jika diketahui Kb air= 0,52° kg/mol.tentukan titik
likoan [24]
Gr terlarut = 36 gr 
<span>Mr terlarut = 180 </span>
<span>gr pelarut = 250 gr </span>
<span>Kb air = 0,52 °C kg/mol </span>

<span>Tb larutan = ........? </span>
<span>--------------------------------------... </span>
<span>ΔTb = Kb.m.i </span>
<span>ΔTb = Kb. (gr t / Mr t) . (1000/ gr p) .i </span>
<span>ΔTb = 0,52 x (36/180) x (1000/250) x 1 </span>
<span>ΔTb = 0,416 °C </span>

<span>Tb = 100 + ΔTb </span>
<span>Tb = 100 + 0,416 </span>
<span>Tb = 100,416 °C</span>
4 0
3 years ago
MOLE CONVERSIONS
madam [21]

Answer:

1.    6.116x1024 Molecules of H2O

2.    13400 L

3.    8.001x1024 Molecules of Mg3(PO4)2

4.    572 g.

5.    1.017x1025 Molecules of N2

6.    7.24 g

.7.     6980 g. of Al(OH)3

8.    3H2 + N2    => 2NH3

9.    S8 + 8O2   => 8SO2

10.  Ni(ClO3)2→     NiCl2   +  3O2

11.  C2H4      +      3O2→      2CO2      +     2H2O

12.  2KClO3→      2KCl      +      3O2

13.  Cu(OH)2   +   2HC2H3O2→     Cu(C2H3O2)2      +     2H2O

14.  C3H8      +      5O2→      3CO2      +      4H2O

15.  191 g of CO

4 0
3 years ago
Calculate the theoretical yield in moles of magnesium chloride when 37 grams of Mg(s) react with 38 grams of HCl(aq).Write the a
goblinko [34]

Answer:

The correct answer is 0.52 moles.

Explanation:

Based on the given question, 37 grams of magnesium reacts with 38 grams of HCl to produce MgCl2 or magnesium chloride. The reaction is:  

Mg (s) + 2HCl (aq) ⇒ MgCl2 (aq) + H2 (g)

There is a need to find the theoretical yield in moles of MgCl2. The formula for calculating the no. or moles is mass/molar mass. Therefore, moles of magnesium is 37/24 = 1.54 and moles of HCl will be 38/36.5 = 1.04.  

From the reaction it is clear that one mole of magnesium reacts with two moles of HCl, as lesser quantity of HCl is present in the given case, therefore, HCl will be the limiting reagent.

Now theoretical moles of magnesium chloride will be,  

= moles of HCl / 2

= 1.04 / 2  

= 0.52 moles

6 0
3 years ago
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