How to find proton electron and neutron on the perdioc table
1 answer:
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In reaction 1 of the Krebs cycle, acetyl‑CoA formed in the pyruvate dehydrogenase reaction condenses with the four‑carbon compound to form <em>citrate </em>with the elimination of coenzyme A. Since the product has three carboxyl groups, this pathway is referred to as the cycle. In reaction 2 of the Krebs cycle, this product then undergoes to form<em> isocitrate. </em>The enzyme is called aconitase because the compound cis‑aconitate is the <em>intermediate product</em> of the reaction. Reaction 3 eliminates CO2 to form the five‑carbon dicarboxylic acid <em>α-cetoglutarate. </em>Oxidation also occurs, with electrons transferred from the substrate to <em>COO-</em> . Consequently, this reaction is an oxidative decarboxylation.
In the image, you can see the reaction 2 in Krebs cycle is a two steps reaction with an intermediate cis-aconitase and a product called isocitrate.
Answer:
The maximum kinetic energy of electron is = 2.93 × Joule
Explanation:
We know that total energy
------------ (1)
Here h = plank's constant = 6.62 × J s
c = speed of light = 3 ×
= 261 nm = 261 ×
m
Put all these values in equation (1) we get
E = 7.6 × J
We know that
Total energy = Energy to remove an electron + K.E of electron
Energy to remove an electron =
Energy to remove an electron = 4.67 × J
K.E of electron = Total energy - Energy to remove an electron
K.E of electron = 7.6 × - 4.67 ×
K.E of electron = 2.93 × Joule
Therefore the maximum kinetic energy of electron is = 2.93 × Joule