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3 years ago

How do the causes of surface and deepwater currents differ

Physics

1 answer:

zepelin [54]3 years ago

5 0

The temperature is colder, and the water pressure is higher.

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tom does not reallt want to give away blue marbles and would like to change the probability that he chooses a blue marble to one

Llana [10]

We don't know how many of ANY color are in the bag right now, so there's no way to calculate an answer.

What Tom has to do is make sure that the number of marbles that are NOT blue is NINE TIMES the number of blue ones in the bag.

4 0

3 years ago

PLEASE HELP!!!

Simora [160]

I only know what number 1. is and its Mechanical Energy.

8 0

3 years ago

What types of ENERGY TRANSFORMATIONS take place when a balloon lights a light bulb?

melomori [17]

Answer:

In the case of an electric bulb, the electrical energy is converted to light and heat. The amount of electrical energy put into a bulb

Explanation:

8 0

3 years ago

(II) A 1200-kg car moving on a horizontal surface has speed v = 85 km/h when it strikes a horizontal coiled spring and is brough

Pie

Answer:

k = 138440 N/m

Explanation:

given,

Mass of the car = 1200 Kg

speed of the car = 85 km/h

= 85 x 0.278 = 23.63 m/s

KE of the car

$KE = \dfrac{1}{2} mv^2$

Using Spring Energy Formula

$KE_{spring}=\dfrac{1}{2}kx^2$

Using conservation of energy

$\dfrac{1}{2} mv^2=\dfrac{1}{2}kx^2$

$k = \dfrac{mv^2}{x^2}$

$k = \dfrac{1200\times 23.63^2}{2.2^2}$

k = 138440 N/m

Spring stiffness constant of the spring is equal to k = 138440 N/m

7 0

3 years ago

Please, I need help!!

Masja [62]

The box has weight 50.0 N (a downward force), from which we can determine its mass $m$ :

$-50.0\,\mathrm N=m(-g)=m\left(-9.80\,\dfrac{\mathrm m}{\mathrm s^2}\right)\implies m=5.10\,\mathrm{kg}$

The box's acceleration is taken to be uniform, which means its acceleration due to the frictional force (which acts in the leftward direction) at any time during the $\Delta t=t_2-t_1=2.25\,\mathrm s$ interval is

$\vec a=\dfrac{0-1.75\,\frac{\mathrm m}{\mathrm s}}{2.25\,\mathrm s}=-0.778\,\dfrac{\mathrm m}{\mathrm s^2}$

Then the friction force has magnitude $F$ (where the vector is acting in the leftward direction) satisfies

$\vec F=m\vec a\implies-F=(5.10\,\mathrm{kg})\left(-0.778\,\dfrac{\mathrm m}{\mathrm s^2}\right)\implies F=3.97\,\mathrm N$

and the closest answer would be A.

8 0

4 years ago