The frictional force is too much compared to the gravitational force
Explanation:
This is because of the great amount of frictional force between the book and the wall.
Also, the force of gravity on the book is not high enough to cause motion of the book to slide downs.
Frictional force is a force that opposes motion.
- For the book to slide down, it must overcome the force of friction acting on it opposite to the direction of gravity.
- According to newton's first law 'a body will remain in its state of rest or uniform motion unless acted upon by an external force'.
- Assuming the external force is gravitational force, clearly we see that the force is less than the frictional exerted on the book by pinning it to the wall.
- This frictional force is a static friction that is on a body at rest, it must be overcome by a larger force before motion takes place.
Fr > fg
Fr is the frictional force
fg is the gravitational force
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The condition of earths atmosphere at a given time and place is the weather.
We can calculate the length of each spring by using the relationship:
where
F is the force applied to the spring
k is the spring constant
x is the length of the spring (measured with respect to its rest position)
Re-arranging the equation, we have
The force applied to both spring is F=60 N. Spring A has spring constant of k=4 N/m, therefore its length with respect to its rest position is
Spring B has spring constant of k=5 N/m, so its length with respect to its rest position is
Therefore, the correct answer is
<span>
D.Spring A is 3 m longer than spring B because 15 – 12 = 3.</span>
Answer:=14,160 kJ
Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below
Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase
C MPa m^3/kg kJ/kg kJ/kg
1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture
2 260 4.689 0.0422 2599 2797 1 Saturated Vapor
The mass initially contained in the tank is m1 = V/v1
m1 =0.85 m^3 /0.02993 m^3 /kg
= 28.4 kg
The mass finally contained in the tank is
m2 =V2/v
= 0.85 m^3 /0.0422 m^3 /kg
= 20.14 kg
The heat transfer is then
Qcv = m2u2 − m1u1 − he(m2 − m1)
Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ
The main difference between series and parallel circuits is that, in series circuits, all components are connected in series so that they all share the same current whereas. In parallel circuits, components are connected in parallel so that they all have the same potential difference between them
