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Vlad [161]
3 years ago
10

PLZ HELP ME Which are not correct statements?

Physics
1 answer:
AURORKA [14]3 years ago
8 0
<span>A. Boyle's law only works when the pressure is constant.
</span><span>D. Charles's law relates volume and pressure.

Hope this helps!</span>
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What is the formula of initial velocity​
inysia [295]
Initial Velocity formulas are used to find the initial velocity of the moving body if some of the terms are given. Initial velocity can be formulated in a unit of a meter per second i.e. ms^{-1}. ms−1.
7 0
3 years ago
Read 2 more answers
Explain how one rock can turn into another
amm1812

Answer:

The rock cycle is the process by which rocks of one kind change into rocks of another kind. ... Metamorphic rock is igneous or sedimentary rock that has been heated and squeezed. It can erode into sediment or melt into magma.

Explanation:

5 0
3 years ago
Your companion on a train ride through Illinois notices that telephone poles near the tracks appear to be passing by very quickl
QveST [7]

Answer:

A) motion parallax

Explanation:

Motion parallax is a visual perception while we are in motion with respect to our surrounding in which the surroundings objects nearer to our eyes appear to move or pass at a faster pace than the objects farther to our eyes during the motion.

This can also be understood as the angular displacement of the objects while our motion. The objects nearer to our eyes have a rapid change in the angular position than the objects far away from us.

3 0
3 years ago
A mass m is attached to an ideal massless spring. When this system is set in motion, it has a period t. What is the period if th
laiz [17]

The period is √2 *T if the mass is doubled to 2m.

What is the time period?

The time period is the length of time during which an activity occurs or a condition remains.

The equation for the period T is given as:

T = 2\pi \sqrt{\frac{m}{k} }

where k is the spring constant

mass of the system = m

Here,

If the mass id doubled to 2m for the system that is set in motion,

new mass is now  2m

So the equation for time period becomes,

T' = 2\pi \sqrt{\frac{2m}{k} }

T' = \sqrt{2} * 2\pi \sqrt{\frac{m}{k} }

T' = \sqrt{2}* T

Hence,

The period is √2 *T if the mass is doubled to 2m.

Learn more about the time period here:

<u>brainly.com/question/17188760</u>

#SPJ4

8 0
2 years ago
In the diagram, q1 = +4.88*10^-8 C.
MAVERICK [17]

Answer:

ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)

Explanation:

The potential difference while moving from point A to Point B is given as follows:

\Delta V = V_B-V_A

where,

ΔV = potential difference from A to B = ?

V_A = Potential at point A = \frac{kq}{r_A}

V_B = Potential at point B = \frac{kq}{r_B}

Therefore,

\Delta V = \frac{kq}{r_B}-\frac{kq}{r_A}\\\\\Delta V = kq(\frac{1}{r_B}-\frac{1}{r_A})

where,

k = Colomb's Constant = 9 x 10⁹ N.m²/C²

q = magnitude of charge = 4.88 x 10⁻⁸ C

r_A = distance of point A from charge = 1.36 m

r_B = distance of point B from charge = 0.538 m

Therefore,

\Delta V = (9\ x\ 10^9\ N.m^2/C^2)(4.88\ x\ 10^{-8}\ C)(\frac{1}{0.538\ m}-\frac{1}{1.36\ m})\\\\\Delta V = (439.2 N.m^2/C)(2.59\ /m)

<u>ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)</u>

7 0
3 years ago
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