Answer:
3/10 F.
Explanation:
Height ( h ) = 1m
Time taken ( t ) = 0.1 second
Height² ( h² ) = 9m
Time taken² ( t² ) = 1 second
Solution,
F = ma
= m ( v - u ) / t
= m √2gh / t
now,
F/F² = √h/h² × t/t²
F¹ = 3/10 F.
answer !!
C. Forces have mass and take up space
The final velocity becomes 31.48 m/s
<u>Explanation:</u>
Given:
Initial velocity, u = 33 m/s
Height, h = 5m
Final velocity, v = ?
According to Newton's law:
v² - u² = 2gh
where,
g is the acceleration due to gravity and
g = 9.8 m/s²
On substituting the values we get:

Therefore, the final velocity becomes 31.48 m/s
The correct answer is:
<span>B.) At terminal velocity there is no net force
In fact, when the parachutist reaches the terminal velocity, his velocity does not change any more. It means that the acceleration acting on the parachutist is zero, and for Newton's second law, this means the net force acting on him is zero:
</span>

<span>because the acceleration is zero: a=0.
This also means that the two relevant forces acting on the parachutist (gravity, downward, and air resistance, upward) are balanced to produce a net force equal to zero.</span>
Answer:
Before start of slide velocity will be 14.81 m/sec
Explanation:
We have given coefficient of static friction 
Angle of inclination is equal to 


Radius is given r = 28 m
Acceleration due to gravity 
We know that 



So before start of slide velocity will be 14.81 m/sec