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vichka [17]
3 years ago
8

Graduated cylinder is filled to 41.5mL with water, and a price of granite is placed in the cylinder displacing the level to 47.6

mL. What is the volume of the granite piece in cubic centimeters
Chemistry
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

6.1 cm³

Explanation:

To solve this problem we first need to keep in mind <em>Archimedes' principle</em>:

  • The volume of water (or any fluid) displaced by a submerged object is equal to the object's volume.

With that in mind we <u>calculate the volume of the granite piece in mililiters</u>:

  • Volume displaced = 47.6 mL - 41.5 mL = 6.1 mL
  • Volume of the granite piece = 6.1 mL

Given that one cubic centimeter is equal to one mililiter, the volume of the granite piece in cm³ is 6.1 cm³.

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The answer is D. It changes the final products of the reaction. .

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150.0 grams of an isotope with a half-life of 36.0 hours is present at time zero. How long will it take
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Initial mass , a = 150 gm .

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The time taken to decay 18.75 gm .

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We know , time taken is given by :

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Putting all given value in above equation :

We get :

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5 0
4 years ago
If 62.8 g Ca react with 92.3 g HCl according to the reaction below, how many grams of hydrogen gas will be produced, and how man
jok3333 [9.3K]

Answer:

2.53 grams of hydrogen gas will be produced and 12.2 many grams of the excess reactant i.e. calcium will be left over.

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Ca + 2HCl\rightarrow CaCl_2 + H_2

Moles of calcium = \frac{62.8 g}{40 g/mol}=1.57 mol

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According to reaction, 2 moles of HCl reacts with 1 mole of calcium :

Then 2.53 moles of HCl will recat with :

\frac{1}{2}\times 2.53 mol= 1.265 mol of calcium.

As we can see moles of calcium are in excessive amount. Hence calcium is an excessive reagent.

Moles of calcium left unreacted =1.57 mol - 1.265 mol =0.305 mol

Mass calcium left unreacted = 0.305 mol × 40 g/mol =12.2 g

Since, calcium is an excessive reagent HCl is limiting reagent and the amount of hydrogen gas produced will depend on HCl .

According to reaction, 2 moles of HCl gives 1 mole of hydrogen gas.

Then 2.53 moles of HCl will give:

\frac{1}{2}\times 2.53 mol= 1.265 mol of hydrogen gas.

Mass of 1.265 mol of hydrogen gas = 1.265 mol × 2 g/mol = 2.53 g

2.53 grams of hydrogen gas will be produced and 12.2 many grams of the excess reactant i.e. calcium will be left over.

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