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Ksenya-84 [330]
3 years ago
13

According to Raoult's law, which statement is false?

Chemistry
1 answer:
irina1246 [14]3 years ago
4 0

Answer:

The answer is (A) Ionic solutes dissociate in solution causing an enhancement of all colligative properties.

Explanation:

When a solute dissociates in solution, it causes changes in colligative properties. In several properties an increase is produced (like in boiling point) whereas in others a decrease is produced (like in melting point and vapor pressure). Colligative properties are these that depend of the number of solute particles there are in a solution. Raoult's law is about vapor pressure of a solvent, and it says that the vapor pressure of a solvent decreases when a solute is added. As greater the number of solute particles in solution, lesser the vapor pressure of the solvent. That is due to the fact that solute particles interact with solvent molecules and avoid its escape to gas phase. So, there are less solute particles in gas phase and consequently its vapor pressure is less.

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Answer:

Sand has less specific heat than water.

Explanation:

Specific Heat is amount of heat needed per unit mass, to raise temperature by 1 degree celsius.

More specific heat means more heat energy needed to increase temperature. It implies - more time needed to absorb heat, increase temperature; and also more time needed to lose its heat.

Less specific heat means less heat energy needed to increase temperature. It implies - less time needed to absorb heat, increase temperature; and also less time needed to lose its heat.

Sand has less specific heat than water. So, it needs less heat absorption to increase temperature by per unit (celsius) ; than water. Hence, same level of heat to both sand & water ; increase temperature of sand more than water, & make it more hot.

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(e)
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Answer:

Hypothesis

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The following electrochemical cell simulates the voltaic cell formed by copper and zinc in seawater at pH 7.90 and 25 ºC.Zn | Zn
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Answer:

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Explanation:

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Zn(s)+2OH^-(aq)\rightarrow Zn(OH)_2(aq)+2 e^-

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Cu(OH)_2(aq)+2e^-\rightarrow Cu(s)+2OH^-(aq)

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