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Sonbull [250]
3 years ago
6

If the box is a distance 1.81 m from the rear of the truck when the truck starts, how much time elapses before the box falls off

the truck?
Physics
1 answer:
alexira [117]3 years ago
4 0
If the box is a distance 1.81 m from the rear of the truck when the truck starts,<span> ... Force of Friction = mu_s * Normal Force( </span>M<span> * G) ... The </span>box starts<span> moving! ... Now that the </span>box<span> is moving, the bed of the </span>truck<span> pulls at it with 17.4 ... out how </span>long<span> it will take the </span>box<span> to reach the back of the </span>truck<span>. ... T^2 = 2 * </span>1.81<span> / .64</span>
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Calculate the work done when a 100-W lightbulb is lit for 30 seconds.
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Answer:

3000 J

Explanation:

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The heat flux that is applied to the left face of a plane wall is q" = 20 w/m2. the wall is of thickness l = 10 mm and of therma
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you ride your bike for a distance of 30km. you travel ata a speed of 0.75km/minute.how many minutes does it take
mihalych1998 [28]
Distance for which the bike is ridden = 30 km
Speed at which the bike is driven = 0.75 km/minute
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Now we already know the formula of speed can be written as
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0.75 = 30/x
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So the time taken for riding a distance of 30 km will be 40 minutes. I hope this procedure is simple enough for you to understand.
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3 years ago
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PLSLPSLLPSLPSLPS HELP I ONLY HAVE 5 MINS PLEASE
UkoKoshka [18]

Answer:

0.19m/s²

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Final velocity(v) = 36.5×1000/60×60

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The circuit shown in the figure (Figure 1) uses a neon-filled tube. This neon lamp has a threshold voltage V0 for conduction, be
Svetllana [295]

Part 1)

Answer:

Explanation:

As we know by equation of charging of the capacitor we will have

V = E(1 - e^{-t/RC})

so we will have

87 = 105(1 - e^{-t/RC})

here we know that

R = 3.00 \times 10^6 ohm

C = 0.250 \mu F

so we have

t = 1.32 s

Part b)

Answer:

The time will increase.

Explanation:

As we know that on increasing the value of the resistance the the product of the resistance and capacitance will increase so the time will increase to get the above voltage.

Part c)

Answer:

The capacitor discharges through a very low resistance (the lamp filled with ionized gas), and so the discharge time constant is very short. Thus the flash is very brief.

Explanation:

Since the lamp resistance is very small so the energy across the lamp will totally lost in very short interval of time

Part d)

Answer:

Once the lamp has flashed, the stored energy in the capacitor is gone, and there is no source of charge to maintain the lamp current. The lamp "goes out", the lamp resistance increases, and the capacitor starts to recharge. It charges again and the process will repeat.

Explanation:

Since we know that the battery is connected to the given system so after whole energy of capacitor is flashed out it is again charged by the battery and the process will continue

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3 years ago
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