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melisa1 [442]
1 year ago
5

Two large, plastic tubs were filled with soil The soil was shaped to create a mound in each tub. The starting height of each mou

nd was recorded. The tubs were set outside, side by side The lid was left off of tub A and a lid was placed on top of tub B Once a day, one ounce of water was poured over the top of each mound for ten days straight At the end of the ten days the mound heights were recorded and compared Is this a valid experimental design to test for wind erosion of soil? А) Yes, because dirt is very heavy B) No, because ten days is not long enough U No, since the type of soil was not identified D Yes, steps were outlined for condition with one variable changed lid on or off​
Physics
1 answer:
shutvik [7]1 year ago
6 0

Answer:

b

Explanation:

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what english word does the following- the first two signify a male, the 1st 3 letters support a female, the first four support a
Zarrin [17]

Answer:

lol i know - i was rushing -_-

he= male

her=female

One word with both is <u>heroin</u> but Im not 100% sure

8 0
2 years ago
A e limb of mass 12kg falls straight down. If air resistance exerts 27 N of froce on the limb as it falls, what is the net force
Gelneren [198K]
During the falling down, two forces are present: gravitational force and air resistance.

So, the net force = mg - f = 12*9.8 - 27 = 90.6 N, the positive sign indicates the direction is pointing towards the center of the earth, which is the same as gravitational force
6 0
2 years ago
A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume
olchik [2.2K]

A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume increases to 30.0 ml, at constant temperature is 0.25atm.

On constant temperature, the pressure and volume relation become constant before and after the change in quantitities have occurred.

According to Boyle's Law,

P₁V₁ = P₂V₂

where, P₁ is pressure exerted by the gas initially

V₁ is the volume of gas initially

P₂ is pressure exerted by the gas finally

V₂ is the volume of gas finally

Given,

P₁ = 1.5 atm

V₁ = 5 ml

V₂ = 30 ml

P₂ =?

On substituting the given values in the above equation:

P₁V₁ = P₂V₂

1.5 atm × 5 ml = P₂ × 30 ml

P₂ = 0.25 atm

Hence, pressure exerted by the gas is 0.25atm.

Learn more about Boyle's Law here, brainly.com/question/1437490

#SPJ4

8 0
1 year ago
What is the Mr of HCO3
kkurt [141]

Answer:

61.0168 g/mol Explanation:

8 0
2 years ago
An 20-cm-long bicycle crank arm, with a pedal at one end, is attached to a 25-cm-diameter sprocket, the toothed disk around whic
Andrej [43]

Answer:

0.033815 m/s²

12.48810875 m

Explanation:

t = Time taken = 12 s

\omega_f = Final angular velocity = 95 rpm

\omega_i = Initial angular velocity = 64 rpm

\alpha = Angular acceleration

\theta = Angle of rotation

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{95\times \frac{2\pi}{60}-64\times \frac{2\pi}{60}}{12}\\\Rightarrow \alpha=0.27052\ rad/s^2

Tangential acceleration is given by

a_t=\alpha r\\\Rightarrow a_t=0.27052\times 0.125\\\Rightarrow a_t=0.033815\ m/s^2

The tangential acceleration of the pedal is 0.033815 m/s²

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{\left(95\times\frac{2\pi }{60}\right)^2-\left(64\times\frac{2\pi}{60}\right)^2}{2\times 0.27052}\\\Rightarrow \theta=99.90487\ rad

Linear displacement would be 99.90487\times \frac{1}{2\pi}\times 2\pi\times 0.125=12.48810875\ m

Length of chain that passes in the interval is 12.48810875 m

4 0
3 years ago
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