When water molecules are disappearing into the air, there is a net ______

a college student produces about 100 kcal of heat per hour on the average what is the rate of energy production and joules

Bond [772]

Given:

Amount of heat produced = 100 kcal per hour

Let's find the rate of energy production in joules.

We know that:

1 calorie = 4.184 Joules

1 kcal = 4.184 Joules

To find the rate of energy production in Joules, we have:

$\begin{gathered} Rate=100\ast4.184 \\ \\ \text{Rate}=418.4\text{ KJ/hour} \end{gathered}$

Therefore, the rate of energy production in joules is 418.4 kJ/h which is equivalent to 418400 Joules

ANSWER:

418.4 kJ/h

6 0

10 months ago

Temperature and pressure of a region upstream of a shockwave are 295 K and 1.01* 109 N/m². Just downstream the shockwave, the te

seraphim [82]

Answer:

change in internal energy 3.62*10^5 J kg^{-1}

change in enthalapy 5.07*10^5 J kg^{-1}

change in entropy 382.79 J kg^{-1} K^{-1}

Explanation:

adiabatic constant $\gamma =1.4$

specific heat is given as $=\frac{\gamma R}{\gamma -1}$

gas constant =287 J⋅kg−1⋅K−1

$Cp = \frac{1.4*287}{1.4-1} = 1004.5 Jkg^{-1} k^{-1}$

specific heat at constant volume

$Cv = \frac{R}{\gamma -1} = \frac{287}{1.4-1} = 717.5 Jkg^{-1} k^{-1}$

change in internal energy $= Cv(T_2 -T_1)$

$\Delta U = 717.5 (800-295) = 3.62*10^5 J kg^{-1}$

change in enthalapy $\Delta H = Cp(T_2 -T_1)$

$\Delta H = 1004.5*(800-295) = 5.07*10^5 J kg^{-1}$

change in entropy

$\Delta S =Cp ln(\frac{T_2}{T_1}) -R*ln(\frac{P_2}{P_1})$

$\Delta S =1004.5 ln(\frac{800}{295}) -287*ln(\frac{8.74*10^5}{1.01*10^5})$

$\Delta S = 382.79 J kg^{-1} K^{-1}$

7 0

2 years ago

A boy drops a coin down a well that is 225 m deep. How long does it take the coin to hit the bottom of the well? (Please state y

Alexxandr [17]

I had the same question. I'm pretty sure it's 23 seconds. :)

7 0

3 years ago

Scientists discover two planets orbiting a distant star. The average distance from the star to Planet A is 8 AU, and it takes 71

Mama L [17]

Answer: 11.2 AU

Explanation:

Applying Kepler's 3rd law, we can find out the average distance of planet B to the star.

This Law states that for planets orbiting a same star, there exists a fixed relationship between the average distance to the star, and the period of his orbit around it, as follows:

K = T² / d³

So , in this case, we can write:

(da)³ / Ta² = (db)³ / (Tb)²

Solving for db:

db = ∛8³.(1170)² / 710² = ∛1390.4 = 11.2 AU

5 0

2 years ago

Beryllium has a nucleus composed of protons and neutrons. Given the data, how many neutrons are in a typical Beryllium nucleus?

shepuryov [24]

Beryllium has a mass number of 9 and 4 protons. To find the number of neutrons you need to subtract the number of protons from the mass number. so...
neutrons = mass - # protons
neutrons = 9 - 4 = 5

6 0

3 years ago

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When water molecules are disappearing into the air, there is a net _______?