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3 years ago

A capacitor is connected to a power source and begins charging.

Physics

2 answers:

Drupady [299]3 years ago

5 0

Answer:

Electrons are too strongly repelled from the negatively charged plate.

Explanation:

A capacitor is a device that stores energy by holding apart pairs of opposite charges. The opposite charges are put in parallel plates. When it's charged by a power source, it's source is sending electrons to the capacitor, thus, it will be put in the negatively charged plate. At some point, the attractive force between the plates will be weaker than the repulsive forces of the electrons and the negatively charged plate, then, they'll be repelled and the capacitor will stop charging.

pashok25 [27]3 years ago

3 0

D.Electrons are too strongly repelled from the negatively charged plate.

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A radar station sends out a 250000 Hz sound wave at a speed of 340 m/s. The sound wave bounces off a weather ballon and returns

Eddi Din [679]

Answers:

a)The balloon is 68 m away of the radar station

b) The direction of the balloon is towards the radar station

Explanation:

We can solve this problem with the Doppler shift equation:

$f'=\frac{V+V_{o}}{V-V_{s}} f$ (1)

Where:

$f=250,000 Hz$ is the actual frequency of the sound wave

$f'=240,000 Hz$ is the "observed" frequency

$V=340 m/s$ is the velocity of sound

$V_{o}=0 m/s$ is the velocity of the observer, which is stationary

$V_{s}$ is the velocity of the source, which is the balloon

Isolating $V_{s}$ :

$V_{s}=\frac{V(f'-f)}{f'}$ (2)

$V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}$ (3)

$V_{s}=-14.16 m/s$ (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.

Now that we have the velocity of the balloon (hence its speed, the positive value) and the time ( $t=4.8 s$ ) given as data, we can find the distance:

$d=V_{s}t$ (5)

$d=(14.16 m/s)(4.8 s)$ (6)

Finally:

$d=68 m$ (8) This is the distance of the balloon from the radar station

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