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3 years ago

Explain how the sizeof particles, catalyst,concerntration and temperature of the substance can affect the rate of reaction?

Chemistry

1 answer:

harkovskaia [24]3 years ago

5 0

Answer:

Look at explanation

Explanation:

Size of particles increases, rate of reaction decreases, and vise versa

Catalyst causes the rate of reaction to increase

Concentration increases, rate of reaction increases, and vise versa

Temperature increases, rate of reaction increases, and vise versa

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Lithium (Li) has 3 electrons. How many shells does an atom of Li have?

Liula [17]

She has 3 I just did that test. Have a good day

8 0

3 years ago

Read 2 more answers

Calcium carbonate+nitic acid

miss Akunina [59]

Answer:

What does calcium carbonate and nitric acid make?

Explanation:

Calcium carbonate reacts with nitric acid to produce carbon dioxide.

is this what you wanted to know?

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3 years ago

The base protonation constant Kb of allantoin (C4H4N3O3NH2) is ×9.1210−6. Calculate the pH of a 1.1M solution of allantoin at 25

larisa [96]

Answer:

pH= 11.5

Explanation:

To the calculation of the pH value, we need to write the ionization equation first. Then using the ICE table and the information given by the problem we can set up the problem:

$C_4H_4N_3O_3NH_2~+~H_2O->C_4H_4N_3O_3NH_3^+~+~OH^-$

I 1.1 M Zero Zero

C -X +X +X

E 1.1-X X X

As next step, using the equilibrium expression for Kb we can replace the terms find in the ICE table and then solve for X, so:

$Kb=\frac{[C_4H_4N_2O_3NH_3^+][OH^-]}{[C_4H_4N_3O_3NH_2]}$

$9.2x10^-^6=\frac{[X][X]}{[1.1-X]}$

$9.2x10^-^6=\frac{X^2}{1.1-X}$

$(9.2x10^-^6)*[1.1-X]=X^2$

$1.01x10^-^5~-9.2x10^-^6X-X^2=0$

$X=0.003173$

With the value of X we can find the pOH (lets remember that X is the concentration of OH-), so:

$pOH=-Log(0.003173)$

$pOH=2.50$

Finally, we can find the pH value with the equation:

$14~=~pH~+~pOH$

$14~=~2.5~+~pOH$

$pH=14-2.5$

$pH=11.5$

The 1.1 M allantoin solution have a pH value of 11.5

4 0

3 years ago

A 3.96x10^-24 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvet; a blank solution containi

viktelen [127]

Actual question from source:-

A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette. A blank had an absorbance of 0.029. The absorbance of an unknown solution of compound A was 0.375. Find the concentration of A in the unknown.

Answer:

Molar absorptivity of compound A = $1502.53\ {Ms}^{-1}$