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Bad White [126]
3 years ago
7

What is the reactant(s) of the reaction below?

Chemistry
1 answer:
svet-max [94.6K]3 years ago
3 0
Answer : C

Reason : The product is MgO which is Magnesium Oxide + CO2 which is carbon dioxide because of the 2
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Palladium (Pd; Z 46) is diamagnetic. Draw partial orbital diagrams to show which of the following electron configurations is con
nexus9112 [7]

Answer : The electron configurations consistent with this fact is, (b) [Kr] 4d¹⁰  

Explanation :

Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom are determined by the electronic configuration.

Paramagnetic compounds : They have unpaired electrons.

Diamagnetic compounds : They have no unpaired electrons that means all are paired.

The given electron configurations of Palladium are:

(a) [Kr] 5s²4d⁸

In this, there are 2 electrons in 's' orbital and 8 electrons in 'd' orbital. From the partial orbital diagrams we conclude that 's' orbital are paired but 'd' orbital are not paired. So, this configuration shows paramagnetic.

(b) [Kr] 4d¹⁰

In this, there are 10 electrons in 'd' orbital. From the partial orbital diagrams we conclude that electrons in 'd' orbital are paired. So, this configuration shows diamagnetic.

(c) [Kr] 5s¹4d⁹

In this, there are 1 electron in 's' orbital and 9 electrons in 'd' orbital. From the partial orbital diagrams we conclude that 's' orbital and 'd' orbital are not paired. So, this configuration shows paramagnetic.

6 0
3 years ago
A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 234 picometers and its
AleksAgata [21]

Answer:

\delta=101.13 g/cm^3

Explanation:

As can be seen in the Figure in a face-centered cubic unit cell you have:

  • Six halves of atoms
  • Eight 1/8 of atom (1 in each corner)

In total:

n_{atom}=6*0.5+8*\frac{1}{8}=4 atoms

Now, each side of the cell is 234 picometers (2.34e-8 cm) long

V_{cell}=L^3=(2.34e^{-8} cm)^3

V_{cell}=1.28*10^{-23}cm^3

Atoms per cm3:

n=\frac{4 atoms}{1.28*10^{-23}cm^3}

n=3.12*10^{23} atoms/cm^3

Expressing in mass:

\delta=3.12*10^{23} atoms/cm^3* \frac{1 mol}{6.022*10^{23}}*195.08 g/mol

\delta=101.13 g/cm^3

6 0
3 years ago
An experimenter places a piece of solid metal weighing 255g into a graduated cylinder which she then fills with mercury. After w
damaskus [11]

Answer: the density of the solid metal is 22.5176 g/cm

Explanation:

Given that;

mass of solid metal = 255 g

the cylinder and its contents weigh 101g less than before

also given that density of mercury = 13.6 g/cm³    

Volume of the solid metal = volume of mercury which was absent in the first weighing

so let volume = Vcm³

Mass of mercury which was absent in the first weighing = density × volume

= 13.6 g/cm³  × Vcm³ = 13.6V g

now since the cylinder and its contents weigh 101g less than before,

it means the difference in mass between the solid and metal and the mass of mercury is equal to 101 g

so

255 - 13.6V g = 101g

13.6V g = 255 g - 101 g

13.6V  = 154

V = 154 /  13.6

V = 11.3245 cm³

Now Density of solid metal will be;

⇒ mass / volume

= 255 / 11.3245

= 22.5176 g/cm

Therefore, the density of the solid metal is 22.5176 g/cm

7 0
3 years ago
Determine the change in volume that takes place when a 3.25-L sample of N2(g) is heated from 250.0 K to 406.8 K. Enter your answ
alexgriva [62]

<u>Answer:</u> The change in volume is 2.05 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.25L\\T_1=250.0K\\V_2=?\\T_2=406.8K

Putting values in above equation, we get:

\frac{3.25L}{250.0K}=\frac{V_2}{406.8K}\\\\V_2=5.30L

Change in volume = V_2-V_1=(5.30-3.25)L=2.05L

Hence, the change in volume is 2.05 L

3 0
3 years ago
what are the names of the "subunits" within the myofibrils that run the length of skeletal muscle fibers?
Shtirlitz [24]

Answer:

Sarcomeres

Explanation:

A muscle fiber is composed of many myofibrils, A sarcomere is the basic unit of a myofibril.

Sarcomeres are arranged in a stacked pattern throughout the muscle tissue, giving it a striped pattern. Sarcomeres are composed of thick and thin filaments. The thin and thick filaments interact  initiate the movement of muscle.

6 0
3 years ago
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