Answer:
Explanation:
The spaceship has traveled 3% of the distance to a space station and it has traveled miles.
Let the total distance from the ship's starting point to the space station be x.
This means that:
The total distance to be traveled is .
Therefore, the distance left to travel is:
The separation between the two slits, d is related to the wavelength, and angle using the formula below. Hence, the value of d is 1.22 x 10⁻⁶ m.
For ease of calculations we take 29.8° = 30°
Using the relation :
where :
d = distance between the slits
θ = 30°
λ = wavelength of light = 617 nm = 6.17 x 10⁻⁷ m
m = 1
Substituting the values into the equation :
d = 1 x 6.17 x 10⁻⁷ / 0.5 = 0.00000122 = 1.22 x 10⁻⁶ m
Therefore, the seperation between the two slits is 1.22 x 10⁻⁶ m.
The double-slit experiment is a demonstration that light and matter can display characteristics of both classically defined waves and particles; moreover, it displays the fundamentally probabilistic nature of quantum mechanical phenomena.
This type of experiment was first performed, using light, by Thomas Young in 1802, as a demonstration of the wave behavior of light. At that time it was thought that light consisted of either waves or particles.
With the beginning of modern physics, about a hundred years later, it was realized that light could in fact show behavior characteristic of both waves and particles. Young's experiment with light was part of classical physics long before the development of quantum mechanics and the concept of wave–particle duality.
Learn more about double-slit experiment here : brainly.com/question/24196355
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Answer:
Options (3) and (6)
Explanation:
Janine drives 2.2 km East.
Since, distances measured in the East are positive,
Displacement = 2.2 km
Then she drives 4.4 km west
Displacement = -4.4 km
Followed by 1.7 km in the East
Displacement = 1.7 km
Total displacement = 2.2 - 4.4 + 1.7 = -0.5 km
km
Total distance covered by Janine = 2.2 + 4.4 + 1.7 = 8.3 km
d = 8.3 km
Therefore, Options (3) and (6) will be the answer.