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3 years ago

I. The substance in model A has the highest density.

Physics

1 answer:

Lynna [10]3 years ago

6 0

Answer:

If you dont have the answer already its i and iii i believe

Explanation:

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A particle moves along the x axis. It is initially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration 20.3

mixas84 [53]

Answer:

a) -2.34 m

b) -1.3 m/s

c) 0.056 m

d) 0.320 m/s

Explanation:

part a

Given:

s(0) = 0.27 m

v(0) = 0.14 m/s

a = -0.320 m/s^2

t = 4.50s

Using kinematic equation of motion for constant acceleration:

s (t) = s(0) + v(0)*t + 0.5*a*t^2

s ( 4.5 s ) = 0.27 + 0.14*4.5 + 0.5*-0.32*4.5^2

s(4.5) = -2.34 m

part b

Using kinematic equation of motion for constant acceleration:

v(t) = v(0) + a*t

v(4.5s) = (0.14) + (-0.32)(4.5) = -1.3 m/s

part c

Use equation for simple harmonic motion:

s(t) = A*cos(w*t)

v(t) = -A*w*sin (w*t)

a(t) = -A*(w)^2 * cos (w*t)

0.27 m = A*cos(w*t) .... Eq 1

0.14 m/s = - A*w*sin (w*t) .....Eq2

-0.320 = -A*(w)^2 * cos (w*t) .... Eq3

Solve the three equations above for A, w, and t

Divide 1 and 3:

w^2 = 0.32 / 0.27

w = 1.0887 rad / s

Divide 2 and 1:

w*tan(wt) = 0.14 / 0.27

tan(1.0887*t) = 0.476289

t = 0.4083 s

A = 0.27 / cos (1.0887*0.4083) = 0.3 m

Hence, the SHM is s(t) = 0.3*cos(1.0887*t)

s(4.5) = 0.3*cos(1.0887*4.5) = 0.056 m

part d

v(t) = - 0.32661 * sin (1.0887*t)

v(4.5) = - 0.32661 * sin (1.0887*4.5) = 0.320 m/s

3 0

3 years ago

Which best compares the gravitational force and the strong force ?

Elan Coil [88]

<span>The heavier the body is, the stronger its gravitational pull. Example, the Milky Way Galaxy has a gravitational pull because of the heavenly bodies such as stars and planets are surrounding it. A strong force is exerted if the mass of another body is bigger than the other body.</span>

8 0

3 years ago

Read 2 more answers

Two blocks of masses 20 kg and 8.0 kg are connected togetherby

Dmitry [639]

Answer:

The tension is 14 N

Explanation:

For this problem we have to use newton's law, so:

$F=m*a$

The second string is connected to the mass of 8 kg, but the mass of 8 kg is connected to the mass of 20kg, so we can say that the second string is handling the two masses. so:

$F=28kg*0.5\frac{m}{s^2}=14N$

3 0

3 years ago

A person with a mass of 72 kg is riding a bicycle is accelerating at a rate of 5m/s on a horizontal surface. What is the weight

nikklg [1K]

Answer:

w = 706.32 [N]

Explanation:

The force due to gravitational acceleration can be calculated by means of the product of mass by gravitational acceleration.

w = m*g

where:

w = weight [N] (units of Newtons)

m = mass = 72 [kg]

g = gravity acceleration = 9.81 [m/s²]

Then we have:

$w = 72*9.81\\w = 706.32 [N]$

7 0

3 years ago

KI + Cl2 ---> KCl + I2<br> Balance the single replacement chemical reaction.

snow_lady [41]

Answer:

2KI + Cl₂ → 2KCl + I₂

Explanation:

The reaction equation is given as:

KI + Cl₂ → KCl + I₂

The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;

aKI + bCl₂ → cKCl + dI₂

Conserving K : a = c

I : a = 2d

Cl : 2b = c

Now let a = 1, c = 1 , d = $\frac{1}{2}$ , b = $\frac{1}{2}$ , ;

Multiply through by 2;

a = 2, b = 1 , c = 2, d = 1

2KI + Cl₂ → 2KCl + I₂

5 0

3 years ago