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3 years ago

5

Why does a balloon stick to a sweater after it has been rubbed against it?

2 answers:

Nataly [62]3 years ago

8 0

Hello,

The balloon sticks to a sweater after it has been rubbed against it because once you rub a balloon against the sweater, the balloon steals electrons from the sweater, which leaves the sweater positively charged and the balloon negatively charged.

Mark brainliest if helped!

Sav [38]3 years ago

3 0

Static electricity. Static electricity is created when positive and negative charges are not balanced.

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Question 16 of 20

marysya [2.9K]

D. Only B and C
Medium and High levels can be harmful. But low even levels aren't good either.

6 0

4 years ago

Determine the critical crack length for a through crack contained within a thick plate of 7150-T651 aluminum alloy that is in un

Mila [183]

Explanation:

Formula to determine the critical crack is as follows.

$K_{IC} = \gamma \sigma_{f} \sqrt{\pi \times a}$

$\gamma$ = 1, $K_{IC}$ = 24.1

[/tex]\sigma_{y}[/tex] = 570

and, $\sigma_{f} = 570 \times \frac{3}{4}$

= 427.5

Hence, we will calculate the critical crack length as follows.

a = $\frac{1}{\pi} \times (\frac{K_{IC}}{\sigma_{f}})^{2}$

= $\frac{1}{3.14} \times (\frac{24.1}{427.5})^{2}$

= $10.13 \times 10^{-4}$

Therefore, largest size is as follows.

Largest size = 2a

= $2 \times 10.13 \times 10^{-4}$

= $20.26 \times 10^{-4}$

Thus, we can conclude that the critical crack length for a through crack contained within the given plate is $20.26 \times 10^{-4}$ .

4 0

3 years ago

a 250.0 g snowball of radius 4.00 cm starts from rest at the top of the peak of a roof and rolls down a section angled at 30.0 d

g100num [7]

Answer:

The response to this question is as follows:

Explanation:

The whole question and answer can be identified in the file attached, please find it.

3 0

3 years ago

wo plates with area 6.00×10−3 m2 are separated by a distance of 1.50×10−4 m . If a charge of 5.40×10−8 C is moved from one plate

liq [111]

Answer:

V = 152.542 volts

Explanation:

Given data:

area of plates $6.00\times 10^{-3} m^2$

distance between the plates is $1.50\times 10^{-4} m$

charge = $5.40\times 10^{-8} c$

we know that capacitance is given as

$C = \frac{\epsilon A}{d}$

$C = \frac{8.85\times 10^{-12} 6\times 10^{-3}}{1.50\times 10^{-4}}$

$C = 3.54\times 10^{-10} F$

potential difference is given as

$V =\frac{Q}{C} = \frac{5.40\times 10^{-8}}{3.54\times 10^{-10}}$

V = 152.542 volts

3 0

4 years ago

Is water weaker than rock?

sveticcg [70]

Answer:

yes, if water was stronger then the rocks would not sink.

Explanation:

4 0

3 years ago

Read 2 more answers