Your pet snake would be found in which kingdom:

In the diagram, above, marker F is pointing to a __________, which are formed when meanders wear away at a narrow point and a po

castortr0y [4]

The answer is <span>oxbow lake</span>

4 0

2 years ago

Read 2 more answers

You step onto a hot beach with your bare feet. A nerve impulse, generated in your foot, travels through your nervous system at a

Masteriza [31]

Answer:

Explanation:

Speed = distance / time

Given speed = 127 m/s .

distance = 1.58 m

time = ?

Putting the values in the formula

127 m/s = 1.58 m / time

time = 1.58 / 127 s

= 12.44 ms .

8 0

3 years ago

Bob is cleaning his dishwasher with white vinegar by putting a bowl of this ____________ mixture in the top of an empty dishwash

Maurinko [17]

Answer: Baking Soda

A mixture of white vinegar and baking soda in a bowl will produce a paste that is helpful in removing stains and sanitizing a dishwasher. To meticulously clean your dishwasher, spread the mixture onto the build-up crust in the bottom basin of the washer itself then let it sit for 15-20 minutes before running a short cycle using the hottest water. The baking soda will further absorb the unpleasant odors and will leave your dishwasher smell fresh.

7 0

2 years ago

Please help me on answer

Molodets [167]

Answer:

The slope is 0.5

Explanation:

It increases so it is positive and it increases by half a block each time so 0.5.

Have an amazing day!

Please rate!

4 0

2 years ago

A hollow, uniformly charged sphere has an inner radius of r1 = 0.105 m and an outer radius of r2 = 0.31 m. The sphere has a net

Sliva [168]

Answer:

E = 77532.42N/C

Explanation:

In order to find the magnitude of the electric field for a point that is in between the inner radius and outer radius, you take into account the Gauss' law for the electric flux trough a spherical surface with radius r:

$\int E\cdot dS=\frac{Q}{\epsilon_o}$ (1)

Q: net charge of the hollow sphere = 1.9*10-6C

ε0: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2

Furthermore, you have that the net charge contained in a sphere of radius r is:

$Q=\rho V=\rho \frac{4\pi (r^3-r_1^3)}{3}$ (2)

with the charge density is:

$\rho=\frac{Q}{\frac{4}{3}\pi(r_2^3-r_1^3)}$ (3)

r2: outer radius = 0.31m

r1: inner radius = 0.105m

The electric field trough the Gaussian surface is parallel to the normal to the surface, the, you have in the integral of the equation (1):

$\int E\cdot dS=E(4\pi r^2)$ (4)

where you have used the expression for a surface of a sphere.

Next, you replace the expressions of equations (2), (3) and (4) in the equation (1) and solve for E:

$E(4\pi r^2)=\frac{1}{\epsilon_o}\frac{Q}{\frac{4}{3}\pi(r_2^3-r_1^3)}(\frac{4\pi (r^3-r_1^3)}{3})\\\\E=\frac{1}{\epsilon_o}\frac{Q(r^3-r_1^3)}{4\pi r^2(r_2^3-r_1^3)}$

you replace the values of all parameters, and with r = 0.17m

$E=\frac{(1.6*10^{-6}C)((0.17m)^3-(0.105m)^3)}{4\pi(8.85*10^{-12}C^2/Nm^2)(0.17m)^2((0.31m)^3-(0.105m)^3)}\\\\E=77532.42\frac{N}{C}$

The magnitude of the electric field at a distance r=0.17m to the center of the hollow sphere is 77532.42N/C

5 0

3 years ago