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4 years ago

This chart lists four elements from the periodic table.

Chemistry

2 answers:

aksik [14]4 years ago

3 0

Iodine and Calcium is the correct answer

PilotLPTM [1.2K]4 years ago

3 0

Answer: d. iodine and calcium

Explanation: Ionic bonds are formed by transfer of electrons between metal and non metals.

Covalent bonds are formed by sharing of electrons between non metals

Electronic configuration of calcium:

$[Ca]=[Ar]4s^2$

Calcium atom will lose two electron to gain noble gas configuration and form calcium cation with +2 charge.

$[Ca^{2+}]={Ar]$

Electronic configuration of iodine:

$[I]=[Kr]4d^{10}5s^25p^5$

Iodine atom will gain one electron to gain noble gas configuration and form iodide ion with -1 charge.

$[I^-]=[Kr]4d^{10}5s^25p^6$

In calcium iodide the one electron from calcium metal gets transferred to iodine atom and thus form an ionic bond to give $CaI_2$

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How much heavier is an alpha particle than an electron?

grandymaker [24]

An electron weighs 1/1836 atomic mass unit and, on the other hand, an alpha particle weighs 4 atomic mass unit.

<span>4 amu / (1/1836 amu) = 7344 </span>

<span>Therefore, an alpha particle is 7344 times heavier than an electron.

Hope this answers the question. Have a nice day.</span>

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4 years ago

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What are the coefficients needed to balance this chemical reaction to show that matter is conserved?

777dan777 [17]

Answer:

Explanation:

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3 years ago

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ruslelena [56]

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3 years ago

Determine the number of milliliters of 0.00300 M phosphoric acid required to neutralize 40.00 mL of 0.00150 M calcium hydroxide.

a_sh-v [17]

The volume of H₃PO₄ : 13.33 ml

<h3>Further explanation</h3>

Given

0.003 M Phosphoric acid-H₃PO₄

40 ml of 0.00150 M Calcium hydroxide-Ca(OH)₂

Required

Volume of H₃PO₄

Solution

Acid-base titration formula

Ma. Va. na = Mb. Vb. nb

Ma, Mb = acid base concentration

Va, Vb = acid base volume

na, nb = acid base valence (amount of H⁺/OH⁻)

H₃PO₄⇒3H⁺ + PO₄³⁻ ⇒ 3 H⁺ = valence = 3

Ca(OH)₂⇒Ca²⁺ + 2OH⁻⇒ 2 OH⁻ = valence = 2

Input the value :

a = H₃PO₄, b = Ca(OH)₂

0.003 x Va x 3 = 0.0015 x 40 x 2

Va = 13.33 ml

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3 years ago

A sample of ethanol (C2H6O) has a mass of 0.2301 g. Complete combustion of this sample causes the temperature of a bomb calorime

Keith_Richards [23]

Answer: $4.994\times 10^{-3}$ moles

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass , occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

Given mass of ethanol = 0.2301

Molar mass of ethanol = 46.07 g/mol

$\text{Number of moles of ethanol}=\frac{0.2301g}{46.07g/mol}=4.994\times 10^{-3}$

Thus there are $4.994\times 10^{-3}$ moles of ethanol are present in the sample.

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4 years ago

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