Answer is: empirical formula for compound is C₂H₆O.
m(CO₂) = 1,6003 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 1,6003 g ÷ 44 g/mol.
n(CO₂) = 0,0364 mol.
n(CO₂) = n(C).
m(C) = 0,0364 mol · 12 g/mol = 0,4368 g.
m(H₂O) = 0,9827 g.
n(H₂O) = 0,9827 g ÷ 18 g/mol.
n(H₂O) = 0,0546 mol.
n(H) = 2 · n(H₂O) = 0,1092 mol.
m(H) = 0,1092 mol · 1 g/mol = 0,1092 g.
m(O) = 0,8376 g - 0,4368 g - 0,1092 g = 0,2916 g.
n(O) = 0,2916 g ÷ 16 g/mol = 0,0182 mol.
n(C) : n(H) : n(O) = 0,0364 mol : 0,1092 mol : 0,0182 mol.
n(C) : n(H) : n(O) = 2 : 6 : 1.
At the sea shore there is less water so the sun shines directly in them, deeper. there is more water. so their bodies are more in the water therefore the sun is less in their bodies.
Listed below are the inter-molecular bonding that exists in the compound <span>ch3ch2ch2ch2ch2ch2oh.
1. Hydrogen Bonding- The type of bonding that exist between O-H in the compound.
2. Dipole-Dipole Bonding- The type of Bonding that is created when the electronegative draws more electron to its self. Exists between C-O
3. London Dispersion- Created between C-H bonding.</span>
The answer is A.) this is because he is moving at a rate that is unknown so we don't know if he is running slower or faster if he is, he is moving by accelerating up or down.
Hope I helped
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