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KATRIN_1 [288]
2 years ago
15

How many liters of hydrogen are needed to produce 34 grams NH3

Chemistry
1 answer:
polet [3.4K]2 years ago
8 0
You would need 1000 liters
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Complete this sentence. If mass remains the same while the volume of a substance ________, the density of the substance will____
VARVARA [1.3K]

Answer:

B. Increases, Decreases

Explanation:

I majored in Chemistry

4 0
3 years ago
PbSO4 → PbSO3 + O2<br> Balance the equation
erastova [34]

Answer:

2PbSO4 → 2PbSO3 + O2

Explanation:

in original equation we notice that we have one extra oxygen, which we cannot form a O2 with, so by multiplying everything else by 2, we get 2 extra oxygen

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3 years ago
How do I find the number of moles and molar mass of Gas A and Gas B with the information provided?
drek231 [11]

Answer:

A.

Explanation:

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3 0
3 years ago
a sample of helium occupies a volume of 101.2 mL at a pressure of 790 mmHg. at what pressure would the volume be 120 mL?
AveGali [126]

Answer : The final pressure will be, 666.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 790 mmHg

P_2 = final pressure = ?

V_1 = initial volume = 101.2 mL

V_2 = final volume = 120 mL

Now put all the given values in the above equation, we get:

790mmHg\times 101.2mL=P_2\times 120mL

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Therefore, the final pressure will be, 666.2 mmHg

6 0
3 years ago
What is Δn for the following equation in relating Kc to Kp?2 SO2(g) + O2(g) ↔ 2 SO3(g)23-2-11
san4es73 [151]

Answer:

-1

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,  

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Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2SO_2_{(g)}+O_2_{(g)}\rightleftharpoons2SO_3_{(g)}

<u>Δn = (2)-(2+1) = -1  </u>

Thus, Kp is:

K_p=  K_c\times (RT)^{-1}

4 0
3 years ago
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