Work is force*displacement if the force and displacement is parallel.
a. You can average the force over the distance so W = Fave*d
<span>b The force part of that multiplication is zero. </span>
<span>c. You can form the average force for the interval from 2 to 3 and find the work for that section and then consider the interval from 3 to 4, find the work and add the 2 work results.
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Answer:
Total 3 holes are available for conduction of current at 300K.
Explanation:
In order to develop a semiconductor, two type of impurities can be added as given below:
- N-type Impurities: Pentavalent impurities e.g. Phosphorous, Arsenic are added to have an additional electron in the structure. Thus a pentavalent impurity creates 1 additional electron.
- P-type Impurities: Trivalent impurities e.g. Boron, Aluminium are added to have a positive "hole" in the structure. Thus a trivalent impurity creates 1 hole.
Now for estimation of extra electrons in the impured structure is as

Now for estimation of "holes" in the impured structure is as

Now when the free electrons and "holes" are available in the structure ,the "holes" will be filled by the free electrons therefore

So total 3 "holes" are available for conduction of current at 300K.
Answer:
The value of d is 183.51 m.
Explanation:
Given that,
Speed of car = 34.0 m/s
Suppose The car race in the circle parallel to the ground surface is at an angle 40°
The radius of circular path 
Normal force acting on the car = N
We need to calculate the value of d
Using component of normal force
The horizontal component of normal force is equal to the gravitational force.
....(I)
The vertical component of normal force is equal to the centripetal force
.....(II)
Divided equation (I) by equation (II)

Put the value of g




Put the value into the formula


Hence, The value of d is 183.51 m.
Answer:
B) R1 = 6 V and R2 = 6V
Explanation:
In series, both resistors will carry the same current.
that current will be I = V/R = 12 / (10 + 10) = 0.6 A
The voltage drop across each resistor is V = IR = 0.6(10) = 6 V