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pashok25 [27]
3 years ago
7

Using the correct answer from Part B, calculate the volume of a rectangular prism with a length of 5.6 cm, a width of 2.1 cm, an

d a height of 6.6 cm.
Chemistry
2 answers:
Vladimir [108]3 years ago
8 0

Answer:

Enter your answer to two significant figures and include the appropriate units = 78 cm^3

Explanation:

son4ous [18]3 years ago
3 0
So the question is asking to compute the volume of a rectangular prism with a length of 5.6 cm,  width of 2.1 cm and a height of 6.6 cm, and base on the said given and using the formula in getting the volume of a rectangular prism, the volume 77.62 cm^3. I hope this would help.
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Nat2105 [25]
You might need to take more pictures so we can see all the equations clearly
4 0
2 years ago
A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 124.0 L and a pressur
amm1812

Answer:

She lost 50.88 moles

Explanation:

Step 1: Data given

The volume of the tank = 124.0 L

The initial pressure = 104.0 atm

The temperature = 24.0 °C = 297 K

The pressure drops to 94.0 atm

The temperature stays constant at 297 K

Step 2: Calculate the initial number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with p = the initial pressure = 104.0 atm

⇒with V = the initial volume = 124.0 L

⇒with n = the initial number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature= 297 K

n = (104.0*124.0)/(0.08206*297)

n = 529.14 moles

Step 3: Calculate final number of moles

p*V = n*R*T

n = (p*V)/(R*T)

⇒with p = the initial pressure = 94.0 atm

⇒with V = the initial volume = 124.0 L

⇒with n = the initial number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature= 297 K

n = (94.0*124.0)/(0.08206*297)

n = 478.26 moles

Step 4: Calculate the difference of moles

529.14 moles - 478.26 moles = 50.88 moles

She lost 50.88 moles

4 0
3 years ago
What is difference between groups and periods? 8th grade science idk what to put it under
d1i1m1o1n [39]
One is rows the other is columns
7 0
2 years ago
The half-life of radon gas is approximately four days. Four weeks after the introduction of radon into a sealed room, the fracti
maksim [4K]

The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>
  • Half-life (t½) = 4 days
  • Time (t) = 4 weeks = 4 × 7 = 28 days
  • Number of half-lives (n) =?

n = t / t½

n = 28 / 4

n = 7

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 100 g
  • Number of half-lives (n) = 7
  • Amount remaining (N)=?

N = N₀ / 2ⁿ

N = 100 / 2⁷

N = 0.78125 g

<h3>How to determine the fraction remaining </h3>
  • Original amount (N₀) = 100 g
  • Amount remaining (N)= 0.78125 g
  • Fraction remaining =?

Fraction remaining = N / N₀

Fraction remaining = 0.78125 / 100

Fraction remaining = 1/128

Learn more about half life:

brainly.com/question/26374513

7 0
2 years ago
When the coffee is brewed according to directions, a pound of coffee beans yields 50 cups of coffee (4 cups = 1 qt). How many kg
Xelga [282]

1 pound of coffee is said to yield 50 cups of coffee

So we need to find the pounds of coffee beans required to produce 250 cups

so if 50 cups need 1 pound of coffee beans

therefore 250 cups need - 1/50 x 250 = 5 pounds of coffee beans

since we have to find the amount of coffee beans needed in kg, we have to convert pounds to kg

1 pound = 0.45 kg

So if 1 pound is equivalent to 0.45 kg

then 5 pounds are equivalent to - 0.45 kg/pound x 5 pounds = 2.25 kg

therefore 2.25 kg of coffee beans are required

4 0
3 years ago
Read 2 more answers
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