Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
Answer:
Step-by-step explanation:
Answer in the attachment
Answer:
it is a convenience sample
Step-by-step explanation:
I assume the heights are 160 ft and 1480 ft.
The two heights are unknown, so we will use variable h to help solve the problem.
The shorter building, building A, has height h.
Since building A is shorter by 160 ft, then building B is taller by 160 ft, so the height of building B is h + 160.
Now we add our two heights to find the total height.
h + h + 160 is the total height.
We can write it as 2h + 160
We are told the total height is 1480 ft, so we let 2h + 160 equal 1480, and we have an equation.
2h + 160 = 1480
Subtract 160 from both sides
2h = 1320
Divide both sides by 2
h = 660
h + 160 = 820
Building A measures 660 ft.
building B measures 820 ft.
Answer:
J+2J=12 so 3J=12 so J=4
Step-by-step explanation:
Use J to represent Jake's miles.
We know that Gloria's miles (G) is twice J, so G=2J
We also know that Jake and Gloria together ran 12 miles.
So we know, J+2J=12 or 3J=12 meaning J=4
So Jake runs 4 miles, and since Gloria is two times that she ran 8 miles.
