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shutvik [7]
3 years ago
14

Speed with direction unit M/S, in a direction

Physics
1 answer:
qwelly [4]3 years ago
3 0

Answer:

Speed is a scalar quantity and does not keep track of direction; velocity is a vector quantity and is direction aware.

Explanation:

I hope this helps you!

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What is the electron configuration of oxygen? 1s22s22p3 1s2, 2s6, 2p4, 3s2 1s2, 2s2, 2p4, 3s2 1s22s22p4
vaieri [72.5K]

oxygen's atomic number is 8

1s22s22p4 is the electron configuration

2+2=4 4+4=8

7 0
3 years ago
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What will be the weight (acceleration due to gravity on the moon is 1/6 that of<br> the earth
jeyben [28]

Answer:

The weight will be 1/6 of whatever it is on Earth.

Explanation:

Remember F=ma

If the acceleration decreases by a factor of 6 while the mass stays constant, you can see the force (the weight) will also decrease by the same factor.

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An archer pulls back the string of a bow to release an arrow at a target. Which kind of potential energy is transformed to cause
Ugo [173]
Elastic Potential Energy because the elasticity in the string stores up the energy.
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INT Raindrops acquire an electric charge as they fall. Suppose a 2.0-mm-diameter drop has a charge of 12 pC; these are both very
horsena [70]

Answer:

W = 2.3 10² F_{e}

Explanation:

The force of the weight is

         W = m g

         

let's use the concept of density

         ρ= m / v

the volume of a sphere is

         V = \frac{4}{3} π r³

         V = \frac{4}{3} π (1.0 10⁻³)³

         V = 4.1887 10⁻⁹ m³

the density of water ρ = 1000 kg / m³

          m = ρ V

          m = 1000 4.1887 10⁻⁹

          m = 4.1887 10⁻⁶ kg

therefore the out of gravity is

          W = 4.1887 10⁻⁶ 9.8

          W = 41.05 10⁻⁶ N

now let's look for the electric force

           F_e = q E

           F_e = 12 10⁻¹² 15000

           F_e = 1.8 10⁻⁷ N

         

the relationship between these two quantities is

          \frac{W}{F_e} = 41.05 10⁻⁶ / 1.8 10⁻⁷

           \frac{W}{F_e} = 2,281 10²

             

             W = 2.3 10² F_{e}

therefore the weight of the drop is much greater than the electric force

3 0
3 years ago
A light flashes at position x=0m. One microsecond later, a light flashes at position x=1000m. In a second reference frame, movin
padilas [110]

Answer:

To the right relative to the original frame.

Explanation:

In first reference frame <em>S</em>,

Spatial interval of the event, \rm \Delta x=1000\ m-0\ m=1000\ m.

Temporal interval of the event, \rm \Delta t = 1\ \mu s=10^{-6}\ s.

In the second reference frame <em>S'</em>, the two flashes are simultaneous, which means that the temporal interval of the event in this frame is \rm \Delta t'=0\ s.

The speed of the frame <em>S' </em>with respect to frame <em>S</em> = v.

According to the Lorentz transformation,

\rm \Delta t'=\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}\left( \Delta t-\dfrac{v\Delta x}{c^2}\right ).\\\\Since,\ \Delta t'=0,\\\therefore \dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}\left( \Delta t-\dfrac{v\Delta x}{c^2}\right )=0\\\Rightarrow \Delta t-\dfrac{v\Delta x}{c^2}=0\\\dfrac{v\Delta x}{c^2}=\Delta t\\v=\dfrac{c^2\Delta t}{\Delta x }.\\\\Also, \ \Delta t,\ \Delta x>0\ \Rightarrow v>0.

And positive v means the velocity of the second frame<em> </em><em>S'</em> is along the positive x-axis direction, i.e., to the right direction relative to the original frame <em>S</em>.

7 0
3 years ago
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