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shutvik [7]
4 years ago
14

Speed with direction unit M/S, in a direction

Physics
1 answer:
qwelly [4]4 years ago
3 0

Answer:

Speed is a scalar quantity and does not keep track of direction; velocity is a vector quantity and is direction aware.

Explanation:

I hope this helps you!

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Object A has a mass m and a speed v, object B has a mass m/2 and a speed 4v, and object C has a mass 3m and a speed v/3. Rank th
Anni [7]

Answer:

Momentum of object A = Momentum of object C < momentum of B.

Explanation:

The momentum of an object is equal to the product of mass and velocity.

Object A has a mass m and a speed v. Its momentum is :

p = mv

Object B has a mass m/2 and a speed 4v. Its momentum is :

p = (m/2)×4v = 2mv

Object C has a mass 3m and a speed v/3. Its momentum is :

p = (3m)×(v/3) = mv

So,

Momentum of object A = Momentum of object C < momentum of B.

5 0
3 years ago
Write 8.54 x 103 in standard notation<br> a. 854,000<br> b. 85,400<br> c. 8,540<br> d. 854
weeeeeb [17]
B. 8540, (assuming you meant 8.54 x 10 to the power 3) you move the decimal point 3 places to the right, if the decimal point can't pass any more numbers add zeros. If it confuses you to think of it this way do 10 cubed first, i.e. 10 x 10 x10 = 1000 and then do 8.54 x 1000 if thats easier for you.
5 0
3 years ago
A falling stone is at a certain instant 90 feet above the ground. two seconds later it is only 10 feet above the ground. if it w
choli [55]

The equation relevant to this is:

S(t) = So + Vot - At²/2 <span>

</span>

<span>Therefore we can create two equations:
<span>S(t) = 90 = So - 4t - 16.1t²                                      --> eqtn  1</span>
<span>S(t+2) = 10 = So - 4(t+2) - 16.1(t+2)²                     --> eqtn 2</span>

</span>

<span>Expanding eqtn 2:
10 = So - 4t - 8 - 16.1(t² + 4t + 4) 
10 = So - 4t - 8 - 16.1t² - 64.4t - 64.4 
10 + 8 + 64.4 = So - 68.4t - 16.1t² 
<span>82.4 = So - 68.4t - 16.1t²                                        --> eqtn 3</span></span>

 <span>
Subtracting eqtn 1 by eqtn 3:</span>

 90 = So - 4t - 16.1t² 

82.4 = So - 68.4t - 16.1t²

 

=> 7.6 = 64.4t

t = 0.118 s

 

Therefore calculating for initial height So:<span>

<span>82.4 = So - 68.4(0.118) - 16.1(0.118)²

<span>So = 90.7 ft</span></span></span>

7 0
3 years ago
An electric heater draws a steady 15.0A on a 120-V
morpeh [17]

Answer:

1. 1800 W

2. $ 17.3

Explanation:

From the question given above, the following data were obtained:

Current (I) = 15 A

Voltage (V) = 120 V

Time (t) = 20 h per day

Duration = 31 days

Cost = 15.5 cents per kWh

1. Determination of the power.

Current (I) = 15 A

Voltage (V) = 120 V

Power (P) =?

P = IV

P = 15 × 120

P = 1800 W

Thus, 1800 W of power is required.

2. Determination of the cost per month (31 days).

We'll begin by converting 1800 W to KW.

1000 W = 1 KW

Therefore,

1800 W = 1800 W × 1 KW / 1000 W

1800 W = 1.8 KW

Next, we shall determine the energy consumption for 31 days. This can be obtained as follow:

Power (P) = 1.8 KW

Time (t) = 2 h per day

Time (t) for 31 days = 2 × 31 = 62 h

Energy (E) =?

E = Pt

E = 1.8 × 62

E = 111.6 KWh

Finally, we shall determine the cost of consumption. This can be obtained as follow:

1 KWh = 15.5 cents

Therefore,

111.6 KWh = 111.6 KWh × 15.5 cents / 1 KWh

111.6 KWh = 1729.8 cents

Converting 1729.8 cents to dollar, we have:

100 cents = $ 1

Therefore,

1729.8 cents = 1729.8 cents × $ 1 / 100 cents

1729.8 cents = $ 17.3

Thus, it will cost $ 17.3 per month to run the electric heater.

4 0
3 years ago
A playground carousel is rotating counterclockwise about its center on frictionless bearings. A person standing still on the gro
Shtirlitz [24]

Answer:

1.94601 rad/s

Explanation:

I_1 = Moment of inertia of carousel = 124 kgm²

\omega_1 = Angular speed of carousel = 3.5 rad/s

\omega_2 = Angular speed of person

r = Radius of carousel = 1.53 m

m = Mass of person = 42.3 kg

Moment of inertia of person

I_2=mr^2\\\Rightarrow I_2=42.3\times 1.53^2\\\Rightarrow I_2=99.02007\ kgm^2

As the angular momentum is conserved in the system

I_1\omega_1=(I_1+I_2)\omega_2\\\Rightarrow \omega=\frac{I_1\omega_1}{(I_1+I_2)}\\\Rightarrow \omega_2=\frac{124\times 3.5}{(124+99.02007)}\\\Rightarrow \omega_2=1.94601\ rad/s

The angular speed of the carousel after the person climbs aboard is 1.94601 rad/s

5 0
3 years ago
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