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shutvik [7]
4 years ago
14

Speed with direction unit M/S, in a direction

Physics
1 answer:
qwelly [4]4 years ago
3 0

Answer:

Speed is a scalar quantity and does not keep track of direction; velocity is a vector quantity and is direction aware.

Explanation:

I hope this helps you!

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Explain why fishes survive in ponds even when the temperature is below 0°c
zmey [24]

Answer:

After sufficient thickness of ice is formed it prevents further loss of heat from the bottom layers of water. This is why fishes and other aquatic animals and plants can survive in ponds and other water bodies even when the atmospheric temperature reaches or is well below 0 degrees.The anomalous expansion of water helps preserve aquatic life during very cold weather. When temperature falls, the top layer of water in a pond contracts becomes denser and sinks to the bottom. ... Thus, even though the upper layer are frozen, the water near the bottom is at 4°C and the fishes can survive in it easily.

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3 years ago
PLEASE ANSWER! WILL MARK BRAINLIEST!
KatRina [158]
The answer is a Mid-Ocean ridge.
5 0
4 years ago
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The first-order rearrangement of CH3NC is measured to have a rate constant of 3.61 × 10–15 s–1 at 298 K and a rate constant of 8
netineya [11]

Answer:

The activation energy for this reaction, Ea = 159.98 kJ/mol

Explanation:

Using the Arrhenius equation as:

ln\frac {K_2}{K_1}=-\frac {E_a}{R}\times (\frac {1}{T_2}-\frac {1}{T_1})

Where, Ea is the activation energy.

R is the gas constant having value 8.314 J/K.mol

K₂ and K₁ are the rate constants

T₂ and T₁ are the temperature values in kelvin.

Given:

K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K

K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K

Applying in the equation as:

ln\frac {8.66\times 10^{-7}}{3.61\times 10^{-15}}=-\frac {E_a}{8.314}\times (\frac {1}{425}-\frac {1}{298})

Solving for Ea as:

Ea = 159982.23 J /mol

1 J/mol = 10⁻³ kJ/mol

Ea = 159.98 kJ/mol

7 0
3 years ago
What type of device is a coal-fired power plant?
Alex777 [14]
I think the answer is D
4 0
3 years ago
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Suppose a 2662 kg giant seal is placed on a scale and produces a 20.0 cm compres- sion. If the seal and spring system are set in
Yuki888 [10]

Answer:

  0.8976 seconds

Explanation:

The period of oscillation for the simple harmonic motion can be found using the formula ...

  T = 2π√(d/g)

where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.

__

For d = 0.20 meters, the period is ...

  T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds

_____

<em>Additional comment</em>

The formula for the oscillator period is usually seen as ...

  T = 2π√(m/k)

where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...

  k = mg/d

Using that in the formula, we find it simplifies to ...

  T=2\pi\sqrt{\dfrac{m}{k}}=2\pi\sqrt{\dfrac{m}{\left(\dfrac{mg}{d}\right)}}=2\pi\sqrt{\dfrac{d}{g}}

5 0
2 years ago
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