I'm only going to complete Part B. The other two are a bit easier and I believe you can do it! :D
Neighborhood A
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Year 1: 30 increased by 20% = 6 more homes.
Year 2: 36 increased by 20% = 7.2 more homes ... 7 more homes. You cannot round in these types of problems.
Year 3: 43 increased by 20% = 8.6 ... 8 more homes.
Year 4: 51 increased by 20% = 10.2 ... 10 more homes.
Year 5: 61 increased by 20% = 12.2 ... 12 more homes.
At the end of 5 years Neighborhood A will have 73 homes in total.
Neighborhood B
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Year 1: 45 +3 = 48
Year 2: 48 +3 = 51
Year 3: 51 +3 = 54
Year 4: 54 +3 = 57
Year 5: 57 +3= 60 homes
After 5 years Neighborhood B will have 60 homes.
Hope this helped! I will do Part A or Part C later if I have time and you still need assistance.
Using Venn probabilities, it is found that the probability that he receives an offer on at least one of the jobs is given by:
D. 0.80
<h3>What is a Venn probability?</h3>
In a Venn probability, two non-independent events are related with each other, as are their probabilities.
The "or probability" is given by:

In this problem, we have that:
- 50% chance of getting an offer on Job A, hence P(A) = 0.5.
- 60% chance of getting an offer on Job B, hence P(B) = 0.6.
- 30% chance of getting an offer on both jobs, hence
.
Then, the probability of getting an offer on at least one job is:

Hence option D is correct.
More can be learned about Venn probabilities at brainly.com/question/25698611
Range is the difference beteeen the smallest and largest numbers in a set.
Therefore, 50-32=18
Look at the attached picture
Hope it will help you
Good luck on your assignment
Have a great day...