Answer:
r = 5.5 ohms
Explanation:
Given:-
- The open circuit voltage, Vo = 3.5 V
- The terminal voltage, Vt = 2.8 V
- The load, R = 22 ohms
- The internal resistance = r
Find:-
What is the generator’s output impedance (pure resistance)?
Solution:-
- We see that the source Voltage (Vo) is not entirely used for the attached load. Some of the source voltage is dropped within due to the source internal resistance or impedance.
- The terminal voltage (Vt) is the amount of Voltage drop across the load. The current drawn by the load I can be determined by Ohm's Law:
Vt = I*R
I = Vt / R
I = 2.8 / 22
I = 0.12727 Amps
- Since, the attached load (R) and the pure impedance (r) of the source are in series. The current ( I ) is constant across both. The potential drop across the pure resistance (r) can be determined from Ohm's law:
Vo - Vt = I*r
r = ( Vo - Vt ) / I
r = ( 3.5 - 2.8 ) / 0.12727
r = 5.5 ohms
Answer: 33.35 minutes
Explanation:
A(t) = A(o) *(.5)^[t/(t1/2)]....equ1
Where
A(t) = geiger count after time t = 100
A(o) = initial geiger count = 400
(t1/2) = the half life of decay
t = time between geiger count = 66.7 minutes
Sub into equ 1
100=400(.5)^[66.7/(t1/2)
Equ becomes
.25= (.5)^[66.7/(t1/2)]
Take log of both sides
Log 0.25 = [66.7/(t1/2)] * log 0.5
66.7/(t1/2) = 2
(t1/2) = (66.7/2 ) = 33.35 minutes
Answer:
I can't understand your language
Answer:
to clear land for agriculture and settlement and to use or sell timber for lumber, paper products, or fuel.
Answer:
The molecular weight will be "28.12 g/mol".
Explanation:
The given values are:
Pressure,
P = 10 atm
= 
= 
Temperature,
T = 298 K
Mass,
m = 11.5 Kg
Volume,
V = 1000 r
= 
R = 8.3145 J/mol K
Now,
By using the ideal gas law, we get
⇒ 
o,
⇒ 
By substituting the values, we get
As we know,
⇒ 
or,
⇒ 
