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Dima020 [189]
2 years ago
14

How many electrons pass through a standard 60 watt light bulb in one second?

Physics
1 answer:
timofeeve [1]2 years ago
6 0
A standard 60 W light bulb has a voltage of 130 volts. So, we use this conversion, the Faraday's constant which is equal to approximately 96,500 Coulombs per mole electron, and the Avogadro's number equal to 6.022×10²³ particles/mole . The solution is as follows:

W = Energy/time
60 W = x J/1 s
x = 60 J = 60 C·V

(60 C·V)*(1/130 V)*(1 mole e/96,500 C)*(6.022×10²³ electrons/mole electron)
= 2.88×10¹⁸ electrons
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a team of dogs is pulling a sled with a net force of 2000 N. The sled is accelerating a 2.2 m/s^2. What is the mass of the sled?
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Force, F = ma

Where m = mass in kg, a = acceleration in m/s²,  Force, F is in N.

F = ma

2000 = m*2.2

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Let the mass of the book be "m", acceleration due to gravity be "g", velocity be "v" and height be "h".

Now if we are holding a book at a certain height (h), <em><u>the potential energy will be maximum which is equal to mass× acceleration due to gravity× height (= mgh)</u>.</em>

(Remember: kinetic energy =0)

Now we consider that the book is dropped, in this case a force will act downward towards the centre of the earth, <em><u>Force= mass× acceleration due to gravity (F=mg)</u></em>. It is equal to the weight of the book.

While the book is falling, the potential energy stored in the book converts into kinetic energy and strikes the floor with <em><u>the maximum kinetic energy= (1/2)×mass×velocity² (=1/2mv²)</u>.</em>

(Remember: kinetic energy=0)

Due to this process the whole energy is conserved.

As the potential energy decreases kinetic energy increases.

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Explanation:

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