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riadik2000 [5.3K]
3 years ago
8

Nalah labels ten rats with the numbers 1 through 10. Then, she records how long it takes each rat to run through a maze. She fin

ds it difficult to graph her data in a line graph. What change could she make to her experimental design that would allow her to plot a clearly displayed data trend in a single line graph?
A) Repeat the experiment ten times. Label the y-axis “Time” and the x-axis “Trial.” Plot the average time for all ten rats for each trial of the experiment.
B) Divide the rats into groups of females and males and repeat. Label the y-axis “Time” and the x-axis “Sex of Rat.” Plot the average time for each group.
C) Repeat the experiment ten times. Label the y-axis “Rat Number” and the x-axis “Time.” Plot the individual time for all ten rats for each trial of the experiment.
D) Divide the rats into two groups based on their speed from the initial data. Label the y-axis “Time” and the x-axis “Group.” Plot the average time for each group.

Answer: A) Repeat the experiment ten times. Label the y-axis “Time” and the x-axis “Trial.” Plot the average time for all ten rats for each trial of the experiment.
Physics
1 answer:
drek231 [11]3 years ago
5 0

Answer:

we have to make another question we maxed it out again lol

Explanation:

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What acceleration is produced when a 12-N force is exerted on a 3-kg object?
lawyer [7]
Using F=Ma
where a= F/M = 12/3 = 4ms-²
3 0
3 years ago
A ship sets sail from Rotterdam, The Netherlands, intending to head due north at 6.5 m/s relative to the water. However, the loc
sattari [20]

Answer:

Explanation:

velocity of ship with respect to water = 6.5 m/s due north

\overrightarrow{v}_{s,w}=6.5 \widehat{j}

velocity of water with respect to earth = 1.5 m/s at 40° north of east

\overrightarrow{v}_{w,e}=1.5\left ( Cos40\widehat{i} +Sin40\widehat{j}\right)

velocity of ship with respect to water = velocity of ship with respect to earth - velocity of water with respect to earth

\overrightarrow{v}_{s,w} = \overrightarrow{v}_{s,e} - \overrightarrow{v}_{w,e}

\overrightarrow{v}_{s,e} = 6.5 \widehat{j}- 1.5\left (Cos40\widehat{i} +Sin40\widehat{j}  \right )

\overrightarrow{v}_{s,e} = - 1.15 \widehat{i}+5.54\widehat{j}

The magnitude of the velocity of ship relative to earth is \sqrt{1.15^{2}+5.54^{2}} = 5.66 m/s

5 0
3 years ago
What is the relationship between the electric force and each one of the charges?
Bess [88]

Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.

3 0
3 years ago
A horizontal 810-N merry-go-round of radius 1.60 m is started from rest by a constant horizontal force of 55 N applied tangentia
Sloan [31]

Answer:

576 joules

Explanation:

From the question we are given the following:

weight = 810 N

radius (r) = 1.6 m

horizontal force (F) = 55 N

time (t) = 4 s

acceleration due to gravity (g) = 9.8 m/s^{2}

K.E = 0.5 x MI x ω^{2}

where MI is the moment of inertia and ω is the angular velocity

MI = 0.5 x m x r^2

mass = weight ÷ g = 810 ÷ 9.8 = 82.65 kg

MI = 0.5 x 82.65 x 1.6^{2}

MI = 105.8 kg.m^{2}

angular velocity (ω) = a x t

angular acceleration (a) = torque ÷ MI

where torque = F x r = 55 x 1.6 = 88 N.m

a= 88 ÷ 105.8 = 0.83 rad /s^{2}

therefore

angular velocity (ω) = a x t = 0.83 x 4 = 3.33 rad/s

K.E = 0.5 x MI x ω^{2}

K.E = 0.5 x 105.8 x 3.33^{2} = 576 joules

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SpyIntel [72]

Distance = (30+40+50) = 120 km

It's back where it started, so displacement = zero

7 0
3 years ago
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