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riadik2000 [5.3K]
3 years ago
8

Nalah labels ten rats with the numbers 1 through 10. Then, she records how long it takes each rat to run through a maze. She fin

ds it difficult to graph her data in a line graph. What change could she make to her experimental design that would allow her to plot a clearly displayed data trend in a single line graph?
A) Repeat the experiment ten times. Label the y-axis “Time” and the x-axis “Trial.” Plot the average time for all ten rats for each trial of the experiment.
B) Divide the rats into groups of females and males and repeat. Label the y-axis “Time” and the x-axis “Sex of Rat.” Plot the average time for each group.
C) Repeat the experiment ten times. Label the y-axis “Rat Number” and the x-axis “Time.” Plot the individual time for all ten rats for each trial of the experiment.
D) Divide the rats into two groups based on their speed from the initial data. Label the y-axis “Time” and the x-axis “Group.” Plot the average time for each group.

Answer: A) Repeat the experiment ten times. Label the y-axis “Time” and the x-axis “Trial.” Plot the average time for all ten rats for each trial of the experiment.
Physics
1 answer:
drek231 [11]3 years ago
5 0

Answer:

we have to make another question we maxed it out again lol

Explanation:

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A steam engine absorbs 4 x 105 J and expels 3.5 x 105 J in each cycle. What is its efficiency?
Wewaii [24]
Input heat, Qin = 4 x 10⁵ J
Output heat, Qout = 3.5 x 10⁵ J

From the first Law of thermodynamics, obtain useful work performed as
W = Qin  -  Qout
     = 0.5 x 10⁵ J

By definition, the efficiency is
η = W/Qin
   = 100*(0.5 x 10⁵/4 x 10⁵)
   = 12.5%

Answer: The efficiency is 12.5%
3 0
3 years ago
The speed of sound in aluminum is 5200 m/s. Can you hear a sound with a
romanna [79]

Answer:

v = wavelength * frequency

frequency = 5200 m/s / .2 m = 26000 / sec

20,000 / sec is optimistic for the upper frequency of human hearing

So 26,000 is above the hearing range for human ears

5 0
3 years ago
9. A sports car travels on a straight road at 22.0 km/h and increases its speed to 57.0 km/h in
Varvara68 [4.7K]

Answer:

4.4 M/s

Explanation:

6 0
3 years ago
The amplitude of a simple harmonic oscillator will be doubled by:a) doubling only the initial speedb) doubling the initial displ
OLEGan [10]

Answer:

When both initial speed and initial displacement is doubled then amplitude will be doubled.

Explanation:

Given that :- Amplitude of simple harmonic Oscillator  is doubled.

So,

     Formula of Simple harmonic oscillator is  X=A\sin\ (2\pi ft +\phi)  ...........(1)

                                                            Where X = Position in (m,cm,km.....)

                                                                        A = Amplitude  in (m,cm,km.....)

                                                                        F = Frequency in (Hz)

                                                                        T = Time in (sec.)

                                                                        Ф = Phase in (rad)

  For initial displacement taking t=0 we get,

                          Initial displacement = A\sin(\phi)    .................(2)            

Now taking equation (1) and differentiating it w.r.t to (t) we get

                                \frac{dx}{dt} = 2\pi fA\cos\ (2\pi ft+\phi)

                                 V= 2\pi fA\cos\ (2\pi ft+\phi)

taking t=0 for initial speed then we get,

                                Initial speed = 2\pi fA\cos\phi    ...............(3)

observing equation (2) & (3) that the initial displacement and initial speed depends on the Amplitude of the Oscillator.

Hence,

when both initial speed and displacement is doubled then amplitude will be doubled.

4 0
4 years ago
A uniform electric field exists in the region between two oppositely charged plane parallel plates. A proton is released from re
valentinak56 [21]

Answer:

a) 17.33 V/m

b) 6308 m/s

Explanation:

We start by using equation of motion

s = ut + 1/2at², where

s = 1.2 cm = 0.012 m

u = 0 m/s

t = 3.8*10^-6 s, so that

0.012 = 0 * 3.8*10^-6 + 0.5 * a * (3.8*10^-6)²

0.012 = 0.5 * a * 1.444*10^-11

a = 0.012 / 7.22*10^-12

a = 1.66*10^9 m/s²

If we assume the electric field to be E, and we know that F =qE. Also, from Newton's law, we have F = ma. So that, ma = qE, and E = ma/q, where

E = electric field

m = mass of proton

a = acceleration

q = charge of proton

E = (1.67*10^-27 * 1.66*10^9) / 1.6*10^-19

E = 2.77*10^-18 / 1.6*10^-19

E = 17.33 V/m

Final speed of the proton can be gotten by using

v = u + at

v = 0 + 1.66*10^9 * 3.8*10^-6

v = 6308 m/s

5 0
3 years ago
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