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3 years ago

How much time does it take for the water to go from the top to bottom 4.5 m/s 53m?

Physics

1 answer:

defon3 years ago

8 0

Takes about an hour and a half maybe

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Please could someone explain this.

icang [17]

This problem is to let you practice using Newton's second law of motion:

Force = (mass) x (acceleration)

-- The airplane's mass when it takes off (before it burns any of its load of fuel) is 320,000 kg.

-- The force available is (240,000 N/per engine) x (4 engines) = 960,000 N.

-- Now you know ' F ' and ' mass '. Use Newton's second law of motion to calculate the plane's acceleration.

7 0

3 years ago

A 65-kg woman in an elevator is accelerating upward at a rate of 0.6 m/s2. The gravitational force is ___ N?

Nastasia [14]

Answer:

The gravitational force is 130.

Explanation:

During this problem you have to multiply the 65 and the 0.6.

5 0

3 years ago

. A PNP transistor is connected in a circuit so that the collector-base junction remains reverse biased and the emitter-base jun

Elodia [21]

Explanation :

A power amplifier is used to amplify electric signals i.e. to increase the low power signal to higher powers.

A PNP transistor is connected in a circuit so that the collector-base junction remains reverse biased and the emitter-base junction is forward biased.

This transistor can be used as a power amplifier because it gives a much larger output current. The gain of an amplifier shows the amount of amplification. It is the difference between the input and the output signals.

6 0

3 years ago

Read 2 more answers

Can work done=mass*acceleration*displacement(work=m*a*s)

Airida [17]

no, work is = force * distance or displacement

5 0

3 years ago

A constant force of 12N is applied for 3.0s to a body initially at rest. The final velocity of the body is 6.0ms–1. What is the

sp2606 [1]

From the question,
$u = 0m {s}^{ - 1}$
$v = 6m {s}^{ - 1}$

$t = 3s$
$F=12N$

Using Impulse, the product of the constant force, F and time t equals the product of the mass of the body and change in velocity.

$Ft =m(v-u)$

$12(3.0)=m(6.0- \: 0)$
This implies that

$36.0 = 6m$
$m = \frac{36.0}{6.0}$
$\therefore \: m = 6.0kg$

You can also use the equation of linear motion,
$v = u + at$
$6 = 0 + a(3)$
$6 = 3a$
$a = \frac{6}{3}$

$a = 2 {ms}^{ - 2}$
But
$F=ma$
$12 = m(2)$
$12 = 2m$
$\frac{12}{2} = m$
$\therefore \: m = 6kg$

4 0

3 years ago