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daser333 [38]
2 years ago
14

Complete the equation for the linear function whose graph contains the points

Mathematics
1 answer:
aniked [119]2 years ago
4 0
Get the slope:
( 10-(-2) )/( 3 - (-1) ) = 3

Let's use letters to represent the ?'s.
y + k = m(x + 1)

Examine the equation:
Notice that if x were to equal -1, the equation would be equal to 0.
m(-1 + 1) = m(0) = 0

If x were to be -1, then y would have to be -2 since that is one of the points provided in the problem.

So now we have:
-2 + k = 0

Solve for k:
k = 2

So I know that 2 is the only number that will work for k.

Our new equation is y + 2 = m(x + 1)

Recall point slope form:
y - y1 = m(x - x1)

Our equation is in the same form as point slope form, so we know that m in our equation represents the slope.

We found the slope at the beginning, it was 3. So plug it in:
y + 2 = 3(x + 1)

Let's test our answer by plugging in a point. Let's try (3, 10):
10 + 2 = 3(3 + 1)
12 = 12

So our answer is correct:
y + 2 = 3(x + 1) is the answer.
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Answer: 10.16 centimeters are in 4 inchs

Step-by-step explanation:

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After 6 hours, a driver had traveled 390 miles. how far had the driver traveled after 4 hours
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Sorry I needed points for an important quiz
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Write a definite integral that represents the area of the region. (Do not evaluate the integral.)
joja [24]

Answer:

\int_{-1}^{1}7(x^{3}-x)\:dx

Step-by-step explanation:

1)  The other curve is y=0 then the common points of both curves are x-intercepts, the roots of y=7(x^{3}-x)

y=7(x^{3}-x)\Rightarrow 7(x^3-x)=0 \Rightarrow 7(x^{3}-x)=7x(x-1)(x-1)\Rightarrow \\S=\left ( 0,0 \right ),\left ( -1,0 \right ),\left ( 1,0 \right )

2). Then those intersection points are the upper and the lower limits. Plugging in to this formula for they belong to the interval [-1,1]:

\int_{a}^{b}|f(x)-g(x)dx

\int_{a}^{b}|f(x)-g(x)dx \Rightarrow \int_{-1}^{1}|7(x^{3}-x)-0|dx \Rightarrow \int_{-1}^{1}7(x^{3}-x)\:dx

 

8 0
3 years ago
Jessica brought 32 kiwi fruit for $16
Crank

Answer:

I think you forgot the context or image of that.

7 0
2 years ago
Read 2 more answers
Birth Weights Babies born after a gestation period of 32-35 weeks have a mean weight of 2600 grams and a standard deviation of 6
lukranit [14]

Answer:

The z-score for the 34-week gestation period baby is 0.61

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score,

μ is the population mean

σ is the population standard deviation.

We are told in the question that:

Babies born after a gestation period of 32-35 weeks have a mean weight of 2600 grams and a standard deviation of 660 grams. Also, we are supposing a 34-week gestation period baby weighs 3000grams

The z-score for the 34-week gestation period baby is calculated as:

z = (x-μ)/σ

x = 3000, μ = 2600 σ = 660

z = 3000 - 2600/660

= 400/660

=0.6060606061

Approximately, ≈ 0.61

6 0
3 years ago
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