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3 years ago

Complete the equation for the linear function whose graph contains the points

1 answer:

4 0

Get the slope:
( 10-(-2) )/( 3 - (-1) ) = 3

Let's use letters to represent the ?'s.
y + k = m(x + 1)

Examine the equation:
Notice that if x were to equal -1, the equation would be equal to 0.
m(-1 + 1) = m(0) = 0

If x were to be -1, then y would have to be -2 since that is one of the points provided in the problem.

So now we have:
-2 + k = 0

Solve for k:
k = 2

So I know that 2 is the only number that will work for k.

Our new equation is y + 2 = m(x + 1)

Recall point slope form:
y - y1 = m(x - x1)

Our equation is in the same form as point slope form, so we know that m in our equation represents the slope.

We found the slope at the beginning, it was 3. So plug it in:
y + 2 = 3(x + 1)

Let's test our answer by plugging in a point. Let's try (3, 10):
10 + 2 = 3(3 + 1)
12 = 12

So our answer is correct:
y + 2 = 3(x + 1) is the answer.

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ANSWERR ASAPP!!! I GIVE BRAINLIESTT!! Answer b and correct c and a if wrong

FrozenT [24]

Answer:

b is (4,55). c is correct I believe.

Step-by-step explanation:

You need to find where the lines cross on the graph. You see that at point (4,55)

6 0

3 years ago

Read 2 more answers

Solve.

Serhud [2]

Answer:

Step-by-step explanation:

12.9 + 10.2x = 35.1

10.2x = 35.1 - 12.9

10.2x = 22.2

x = 22.2/10.2

x= 222/102 = 111/51

$x= 2\dfrac{9}{51}$

6 0

3 years ago

Read 2 more answers

What’s -2x+y= -14 6x + 5y = -6

Katarina [22]

Hey, here's a pic of it ! hope this helps !

p.s., photomath is a good app for algebraic answers with work, you should check it out (:

3 0

3 years ago

The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f

Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen who carry a credit card balance.

The formula for the interval is:

p'₁± $Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }$

$Z_{1-\alpha /2}= Z_{0.95}= 1.648$

0.37±1.648* $\sqrt{\frac{0.37*0.63}{1000} }$

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂± $Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }$

0.48±1.648* $\sqrt{\frac{0.48*0.52}{1000} }$

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: $\sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015$

Seniors: $\sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016$

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0

3 years ago

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Roman55 [17]

Answer:

Standard error (S.E) = 0.048 ≅ 0.05

Step-by-step explanation:

Explanation:-

Given sample size 'n'=76

Given the dean who randomly selects 76 students and finds that 58 out of 76 are receiving financial aid.

Sample proportion

$p = \frac{x}{n} = \frac{58}{76} = 0.7631$