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Given:
The equation of a circle is
A tangent line l to the circle touches the circle at point P(12,5).
To find:
The gradient of the line l.
Solution:
Slope formula: If a line passes through two points, then the slope of the line is
Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is
We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.
Product of slopes of two perpendicular lines is always -1.
Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.
Therefore, the gradient or slope of the tangent line l is .
Answer:
Step-by-step explanation:
Given
Co ordinates of vertices(1,-6) and (-8,-6)
When two points is given then Length of two points is given by
Perimeter of rectangle is =26 units
Let the other side be x
thus
x+9=13
x=4 units
therefore to get the other two co ordinates
such that the length of that side is 4 units is
Horizontal distance will remain same only vertical distance will change in given co ordinates to obtain the remaining two co ordinates
To verify the above two distance between two points must be 13 units