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jeyben [28]
4 years ago
10

3 markers cost $5.79.

Mathematics
2 answers:
bazaltina [42]4 years ago
5 0

A is the ans

3-5.97

13-x

Cross multiply

lord [1]4 years ago
4 0

Answer:

C. 3/$5.79 = 13/x

Step-by-step explanation:

We can write the fact that 3 markers cost $5.79 as a proportion:

3/$5.79

Let x represent the unknown cost of 13 markers. Since 13 markers cost x, we have the following proportion:

13/x

The cost changes along with the number of markers purchased, and so the two proportions are equivalent.

3/$5.79 = 13/x

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lisa and bob drove 100 miles on their vacation. lisa drove 22 miles more than bob drove. how many miles did each drive?
muminat
100=(22+bob)+bob
Bob=78/2
Bob=39
Lisa= 39+22
Bob drove 39 miles
Lisa drove 61 miles
3 0
3 years ago
In the integer card game, you drew the cards,2,8,and -11. Your partner gave you a 7 from his hand. A. What is your total? B. Wha
Flauer [41]

a) At this point, your total is 6.

b) You need to draw a card with the number -6.

<h3>What is your total?</h3>

In the integer card game, your total is equal to the sum of the values in your cards.

So, you have 2, 8, and -11, and then your partner gave you a 7 from his hand, then your total will be:

T = 2 + 8 + (-11) + 7 = 17 - 11 = 6

At this point, your total is 6.

<h3>b) What cards would you need to get your score back to zero? </h3>

The value of the card must be such that when we add the value of the card to the current total, the outcome is 0.

So the value of the card must be equal to the additive inverse of your total, where the additive inverse of a number is another number such that when you add these two numbers the outcome is 0.

So if your total is 6, then:

6 + a = 0

a = -6

This means that you need to draw a card with the number -6.

If you want to learn more about additive inverses:

brainly.com/question/1548537

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4 0
1 year ago
One of the legs of right triangle measures 16 cm and the other leg measures 2 cm.
Pavlova-9 [17]

Answer:

16.1 cm (nearest tenth)

Step-by-step explanation:

<u>Pythagoras’ Theorem</u>

a^2+b^2=c^2

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

Given:

  • a = 16 cm
  • b = 2 cm

Substitute the given values into the formula and solve for c:

\implies 16^2+2^2=c^2

\implies 256+4=c^2

\implies c^2=260

\implies c=\sqrt{260}

\implies c=2\sqrt{65}

\implies c=16.1 \sf \: cm\:(nearest\:tenth)

3 0
2 years ago
The rate of change of the downward velocity of a falling object is the acceleration of gravity (10 meters/sec 2) minus the accel
Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Write the initial value problem and the solution for the downward velocity for an object that is dropped (not thrown) from a great height.

if v(t) is the speed at time t after being dropped, v'(t) is the acceleration at time t, so the the initial value problem for the downward velocity is

v'(t) = 10 - 0.1v(t)

v(0) = 0 (since the object is dropped)

<em> The equation v'(t)+0.1v(t)=10 is an ordinary first order differential equation with an integrating factor </em>

\bf e^{\int {0.1dt}}=e^{0.1t}

so its general solution is  

\bf v(t)=Ce^{-0.1t}+100

To find C, we use the initial value v(0)=0, so C=-100

and the solution of the initial value problem is

\bf \boxed{v(t)=-100e^{-0.1t}+100}

what is the terminal velocity?

The terminal velocity is

\bf \lim_{t \to\infty}(-100e^{-0.1t}+100)=100\;mt/sec

How long before the object reaches 90% of terminal velocity?

90%  of terminal velocity = 90 m/sec

we look for a t such that

\bf -100e^{-0.1t}+100=90\rightarrow -100e^{-0.1t}=-10\rightarrow e^{-0.1t}=0.1\\-0.1t=ln(0.1)\rightarrow t=\frac{ln(0.1)}{-0.1}=23.026\;sec

How far has it fallen by that time?

The distance traveled after t seconds is given by

\bf \int_{0}^{t}v(t)dt

So, the distance traveled after 23.026 seconds is

\bf \int_{0}^{23.026}(-100e^{-0.1t}+100)dt=-100\int_{0}^{23.026}e^{-0.1t}dt+100\int_{0}^{23.026}dt=\\-100(-e^{-0.1*23.026}/0.1+1/0.1)+100*23.026=1,402.6\;mt

3 0
3 years ago
Kamden is a mind-reading alien. He had each friend draw and look at a card, then he guessed whether the card had a star on it.
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Answer:

what are u asking?

Step-by-step explanation:

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3 years ago
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