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ExtremeBDS [4]
3 years ago
14

Justin plans to spend $35 on sports cards. Regular cards cost $4.50 per pack and foil cards cost $6.00 per pack Which inequality

shows the relationship between the number of packs of regular cards (r) and the number of packs of foll cards (f) Justin can afford to buy?
Mathematics
1 answer:
Dmitriy789 [7]3 years ago
3 0

Answer:Justin plans to spend $20 on sports cards. Regular cards cost $3.50 per pack and foil cards cost $4.50 per pack

number of packs of regular cards =r and the number of packs of foll cards = f

Cost of Regular card = 3.50

Cost of 'r' packs of regular card = 3.50r

Cost of Foil card = 4.50

Cost of 'f' packs of Foil card = 4.50f

Justin plans to spend $20 on sports cards so the sum of cost of regular and Foil cards should be less than or equal to 20

The inequality becomes

3.50r + 4.50f <= 20

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Answer:

7. 25% of the merchants who purchase goods from Asia also purchase from Europe.

Step-by-step explanation:

I am going to say that:

A is the percentage of merchants who purchase goods from Asia.

B is the percentage of merchants who purchase goods from Europe.

We have that:

A = a + (A \cap B)

In which a is the probability that a merchant purchases goods from Asia but not from Europe and A \cap B is the probability that a merchant purchases goods from both Asia and Europe.

By the same logic, we have that:

B = b + (A \cap B)

Which of following statement is individually sufficient to calculate what percent of the merchants in the group purchase goods from Europe but not form Asia?

We already have B.

Knowing A \cap B, that is, the percentage of those who purchase from both Asia and Europe, we can find b.

So the correct answer is:

7. 25% of the merchants who purchase goods from Asia also purchase from Europe.

8 0
3 years ago
Owen has $7000 in a savings account and $3000 invested in the stock market, he owns a car worth $12,000, he has $13,000 left to
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3 0
3 years ago
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Step-by-step explanation:

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