a steep-sided valley formed by the downward displacement of a block of the earth's surface between nearly parallel faults or fault systems.
<span>v(4 seconds)= 300 m/s - 9.8 (m/s^2)(4s) = 260.8 m/s </span>, hope this helps:)
The jet fighter's acceleration at the highest point is 17.56 ft/s²
The jet fighter's acceleration at the lowest point is 35.12 ft/s²
The given parameters;
radius of the circular path, r = 1200 ft
constant velocity, v = 140 mi/h = 205.3 ft/s
The formula for centripetal acceleration in a circular path is given as;
The jet fighter's acceleration at the highest point is calculated as;
h = 2r = 2 x 1200 ft = 2,400 ft
The jet fighter's acceleration at the lowest point is calculated as;
h = r = 1,200 ft
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The equation we use is mλ=dsinθ for intensity maximas. We are given at the first maximum (m=1), it occurs at 17.8 degrees. Thus we can solve for d by substituting known values into our equation.
(1) (632.8*10^-9m)=dsin(17.8) => d = 2.07*10^-6m
Next we want to find the angle at the second maximum (m=2) so we need to solve for θ.
(2) (632.8*10^-9m) = (2.07*10^-6m)sinθ
θ=37.69 degrees
Hopes this helps!
P.S. I hope this is right. If not sorry in advance.
Answer:
Explanation:
The cross product of two vectors is given by
Where, θ be the angle between the two vectors and \widehat{n} be the unit vector along the direction of cross product of two vectors.
Here, K x i = - j
As K is the unit vector along Z axis, i is the unit vector along X axis and j be the unit vector along axis.
The direction of cross product of two vectors is given by the right hand palm rule.
So, k x i = j
j x i = - k
- j x k = - i
i x i = 0