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pav-90 [236]
3 years ago
9

What mass needs to be attached to a spring with a force constant of 7N/m in order to make a simple harmonic oscillator oscillate

with a time period of 3s
Physics
1 answer:
Alex_Xolod [135]3 years ago
6 0

Answer:

Mass will be 4.437 kg

Explanation:

We have given force constant k = 7 N/m

Time period of oscillation T = 5 sec

So angular frequency \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{5}=1.256rad/sec

We know that angular frequency is given by

\omega =\sqrt{\frac{k}{m}}

1.256 =\sqrt{\frac{7}{m}}

Squaring both side

1.577 =\frac{7}{m}

m = 4.437 kg

You might be interested in
How does heat affect the thermal energy of an object that is colder than the qir
podryga [215]

Answer:

the correct answer is B

Explanation:

thermal energy makes heat increase.

4 0
3 years ago
How much tension must a cable withstand to accellerate a 1400 kg car vertically upward at 0.70 m/s^2
MariettaO [177]

Answer:

Below

Explanation:

The cars upward accel adds to the gravity accel (think about how suddenly heavy you feel when the elevator starts to move upward)

F = tension = ma

                   = 1400 * ( .7 + 9.81) = 14714 N

7 0
2 years ago
Challenge! A marshmallow is dropped from a 5-meter high pedestrian bridge and 0.83 seconds later, it lands right on the head of
WINSTONCH [101]

a₀).  You know ...
         -- the object is dropped from 5 meters
             above the pavement;
         --  it falls for 0.83 second.

a₁).  Without being told, you assume ...
         -- there is no air anyplace where the marshmallow travels,
             so it free-falls, with no air resistance;
         -- the event is happening on Earth,
            where the acceleration of gravity is  9.81 m/s² .

b).  You need to find how much LESS than 5 meters
       the marshmallow falls in 0.83 second.
    
c).  You can use whatever equations you like.
       I'm going to use the equation for the distance an object falls in
       ' T ' seconds, in a place where the acceleration of gravity is ' G '.

d).  To see how this all goes together for the solution, keep reading:


The distance that an object falls in ' T ' seconds
when it's dropped from rest is

                                 (1/2 G) x (T²) .

On Earth, ' G ' is roughly  9.81 m/s², so in 0.83 seconds,
such an object would fall

                               (9.81 / 2) x (0.83)² = 3.38 meters .

It dropped from 5 meters above the pavement, but it
only fell 3.38 meters before something stopped it.
So it must have hit something that was

                         (5.00 - 3.38)  =  1.62 meters

above the pavement.  That's where the head of the unsuspecting
person was as he innocently walked by and got clobbered.

7 0
3 years ago
The surface charge density on an infinite charged plane is −1.70 x 10^−6 C/m^2 . A proton is shot straight away from the plane a
goldfiish [28.3K]

Answer:

Acceleration of proton will be -9.197\times 10^{12}m/sec^2

Explanation:

We have given surface charge density of an infinite charged plate \sigma = -1.70\times 10^{-6}C/m^2

Electric field due to infinite sheet charge is given by E=\frac{\sigma }{2\epsilon _0}=\frac{-1.7\times 10^{-6}}{2\times 8.85\times10^{-12}}=-0.096\times 10^6=-9.6\times 10^4N/C

Charge in proton is given by e=1.6\times 10^{-19}C

So force on proton F=qE=1.6\times 10^{-19}\times -9.6\times 10^4=-15.36\times 10^{-15}N

Mass of proton m=1.67\times 10^{-27}kg

According to newtons second law force F = mass × acceleration

So -15.36\times10^{-15}=1.67\times 10^{-27}a

a=-9.197\times 10^{12}m/sec^2

3 0
3 years ago
What units are vector units
Sindrei [870]
It is two 2d d1 2d I knew It because I am graduating from college .
3 0
3 years ago
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