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dalvyx [7]
3 years ago
5

Name three categories that are used to classify the elements in the periodic table?

Physics
2 answers:
dusya [7]3 years ago
7 0

Metals, non-metal and noble gases are the three categories useful for classifying the elements in periodic table.

<u>Explanation:</u>

Elements are defined as a vertical group and a horizontal period in periodic table. Metals, non-metal and noble gases are the three categories useful for classifying the elements in periodic table.

A large number of elements in periodic table flow under the Metals category. Non-metal in the table are mostly gaseous. Noble gases in the table are colorless and non-reactive.

nikitadnepr [17]3 years ago
6 0

Answer:

metals,nonmetals, and inert gases

Explanation:

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Can two similar charges attracts each other ? ​
VMariaS [17]

Answer:

no they cannot, only opposite charges attract

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3 years ago
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The force exerted on the tires of a car that directly accelerate it along a road is exerted by the
azamat

The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

<h3>What is force?</h3>

Force is defined as the product of mass and acceleration of an object.

Friction is defined as the force that resists the movement of an object over another.

Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.

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7 0
2 years ago
Olivia is on a swing at the playground at which point is her kinetic energy increasing and her potential energy decreasing
Nimfa-mama [501]
Whenever an object is falling, its potential energy
is decreasing and its kinetic energy is increasing.

Olivia's potential energy is decreasing and her kinetic energy
is increasing as she moves toward the right side of the picture,
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3 years ago
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A physics student swings a pail of water in a vertical circle 1.0 m in radius at a constant speed. If the water is NOT to spill
love history [14]

Answer:

(A) 3.1 m/s

(B) 2.0 s

Explanation:

At the minimum speed, the force of gravity equals the centripetal force.

mg = m v² / r

v = √(gr)

v = √(9.8 m/s² × 1.0 m)

v = 3.1 m/s

The time is the circumference divided by the speed.

t = (2π × 1.0 m) / (3.1 m/s)

t = 2.0 s

7 0
3 years ago
A 90 kg man stands in a very strong wind moving at 17 m/s at torso height. As you know, he will need to lean in to the wind, and
victus00 [196]

Answer:

a)  t=195.948N.m

b)  \phi=13.6 \textdegree

Explanation:

From the question we are told that:

Density \rho=1.225kg/m^2

Velocity of wind v=14m/s

Dimension of rectangle:50 cm wide and 90 cm

Drag coefficient \mu=2.05

a)

Generally the equation for Force is mathematically given by

F=\frac{1}{2}\muA\rhov^2

F=\frac{1}{2}2.05(50*90*\frac{1}{10000})*1.225*17^2

F=163.29

Therefore Torque

t=F*r*sin\theta

t=163.29*1.2*sin90

t=195.948N.m

b)

Generally the equation for torque due to weight is mathematically given by

t=d*Mg*sin90

Where

d=sin \phi

Therefore

t=sin \phi*Mg*sin90

195.948=833sin \phi

\phi=sin^{-1}\frac{195.948}{833}

\phi=13.6 \textdegree

5 0
3 years ago
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