Yes, it was demonstrated that the masses of the 4 different baskets differ meaningfully.
If we compare the two ranges, the differences are significant because the error range for the same basket was less than the differences between different baskets.
The Error range is a measurement of the degree of uncertainty attached to a number and is defined as the difference between the greatest and lowest error values.
So, Yes the baskets masses differ by more than the range of measurement error that was obtained by repeatedly measuring the mass of one basket.
Learn more about Experimental Errors herehttps://brainly.com/question/17648352
#SPJ4
Answer:
The average atomic mass of X is 206.0346
Explanation:
Atomic mass of 200X = 200.028
% abundance of 200X = 40% = 40/100 = 0.4
Atomic mass of 210X = 210.039
% abundance of 210X = 100% - 40% = 60% = 60/100 = 0.6
Average atomic mass of X = (0.4×200.028) + (0.6×210.039) = 80.0112 + 126.0234 = 206.0346
<h2>Hope it's helpful for you ✌️✌️✌️✌️✌️</h2>
Answer:
Waves with high frequencies have shorter wavelengths that work better than low frequency waves for successful echolocation.
Explanation:
To understand why high-frequency waves work better than low frequency waves for successful echolocation, first we have to understand the relation between frequency and wavelength.
The relation between frequency and wavelength is given by
λ = c/f
Where λ is wavelength, c is the speed of light and f is the frequency.
Since the speed of light is constant, the wavelength and frequency are inversely related.
So that means high frequency waves have shorter wavelengths, which is the very reason for the successful echolocation because waves having shorter wavelength are more likely to reach and hit the target and then reflect back to the dolphin to form an image of the object.
Thus, waves with high frequencies have shorter wavelengths that work better than low frequency waves for successful echolocation.
Hello!
Vx = V0x + Ax*t
Vx = 18.1 + 2.4t
Let’s take time as 7.50 seconds:
Vx = 18.1 + 2.4*7.50
Vx = 18.1 + 18 = 36.1 m/s
Then, the final velocity of the car is 36.1 m/s.