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MariettaO [177]
3 years ago
15

Some elements are highly unstable and break apart within seconds, making them difficult to study. How can the periodic table hel

p scientists infer the properties of these elements?
Physics
2 answers:
rusak2 [61]3 years ago
8 0
You can look at groups in the same group (the columns), since they tend to have similar properties. For example, the alkali metals in group one react aggressively with water and form white compounds.
cricket20 [7]3 years ago
4 0

Answer:

By checking the properties of elements with the same atomic number as the unstable elements.

Explanation:

For elements that are unstable but have known number of electrons or protons, their chemistry can be inferred from the periodic table by comparing them with elements with similar number of electrons or protons.

<em>Elements with the same number of protons but different number of neutrons are referred to as isotopes.</em> They usually have the similar properties except that they have different number of neutrons and hence, different atomic mass.

Since the number of proton determines the atomic number of elements, such element's properties can be inferred by checking the properties of elements with the same atomic number on the periodic table.

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3 years ago
A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 35 m/s2 for 35 s , then ru
r-ruslan [8.4K]

Answer:

T = 295.57 s

Explanation:

given,

mass of the rocket = 200 Kg

mass of the fuel = 100 Kg

acceleration = 35 m/s²

time, t = 35 s

time taken by the rocket to hit the ground, = ?

Final speed of the rocket when fuel is empty

using equation of motion

v = u + a t

v = 0 + 35 x 35

v = 1225 m/s

height of the rocket where fuel is empty

v² = u² + 2 a s

1225² = 0 + 2 x 35 x h₁

h₁ = 21437.5 m

After 35 s the rocket will be moving upward till the final velocity becomes zero.

Now, using equation of motion to find the height after 35 s

v² = u² + 2 g h₂

0² = 1225² + 2 x (-9.8) h₂

h₂ = 76562.5 m

total height = h₁ + h₂

          = 76562.5 m + 21437.5 m = 98000 m

now, time taken by before the rocket hit the ground

using equation of motion

s = u t +\dfrac{1}{2}at^2

-13500 = 1225 t -\dfrac{1}{2}\times 9.8 \times t^2

negative sign is used because the distance travel by the rocket is downward.

4.9 t² - 1225 t - 13500 = 0

t = \dfrac{-(-1225)\pm \sqrt{1225^2 - 4\times 4.9 \times (-13500)}}{2\times 4.9}

t = 260.57 s

neglecting the negative sign

total time the rocket was in air

T = t₁ + t₂

T = 35 + 260.57

T = 295.57 s

Time for which rocket was in air is equal to 295.57 s.

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