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3 years ago

What are 5 facts about the enviorment in the Atacama Desert?

2 answers:

8 0

The Atacama Desert is a plateau in South America.

Covering a 1,000-kilometre strip of land on the Pacific coast.

West of the Andes mountains. It is the driest non-polar desert in the world.

In the late 1800s, Chile and Bolivia disputed this land in the Guerra del Pacífico (War of the Pacific) becaue both countries claimed to be rightful owners of this region that.

During the day, temperatures in the desert can reach around 40º C (104º F).

boyakko [2]3 years ago

7 0

5 facts

- The Atacama Desert is located in South America
- Covers an area of approximately 128,000 square kilometers
- The Atacama Desert is home to many species of animals including insects and arachnids, reptiles and amphibians, mammals and birds.
- Many species of plant life can be found growing in the Atacama Desert including trees, shrubs, cacti, herbs and grasses.
- It is among the most driest places on Earth as it receives little to no rainfall.

Hopefully that works! :))

You might be interested in

Non metals are acidic in nature explain with an equation

natka813 [3]

When non metallic oxide for example SO2 dissolved in water it produces sulphurous acid. SO2 + H2O → H2SO3 When metallic oxide reacts with water it produces Metal hydroxides. Na2O + H2O → 2NaOH

6 0

3 years ago

How to calculate the pH of NH4OH(0.1M)

anastassius [24]

Answer is: pH of ammonium hydroxide is 11.13.
Chemical reaction of ammonium hydroxide in water: NH₄OH → NH₄⁺ + OH⁻.

Kb(NH₄OH) = 1,8·10⁻⁵.
c₀(NH₄OH) = 0.1 M.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₄OH) = 0.1 M- x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₄OH).
0,000018 = x² / 0.1 mol/L - x.

Solve quadratic equation: x = c(OH⁻) = 0.00133 M.

pOH = -logc(OH⁻).

pOH = 2.87.

pH = 14 - 2.87.

pH = 11.13.

8 0

3 years ago

How many valence electrons should be used to draw a Lewis structure of methane CH4

olganol [36]

Answer:

8 valence electrons

Explanation:

There are 4 valence electrons in carbon because it is in group 4A of the periodic table. There is 1 valence electron per hydrogen based on its position on the periodic table, but CH4 has 4 hydrogens in it. So 1 times 4 is 4. Add the 4 valence electrons from carbon with the 4 electrons from H4 to get 8.

8 0

3 years ago

Nitrogen and hydrogen combine to form ammonia in the Haber process. Calculate (in kJ) the standard enthalpy change ΔH° for the r

PolarNik [594]

Answer: -105 kJ

Explanation:-

The balanced chemical reaction is,

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

The expression for enthalpy change is,

$\Delta H=\sum [n\times B.E(reactant)]-\sum [n\times B.E(product)]$

$\Delta H=[(n_{N_2}\times B.E_{N_2})+(n_{H_2}\times B.E_{H_2}) ]-[(n_{NH_3}\times B.E_{NH_3})]$

$\Delta H=[(n_{N_2}\times B.E_{N\equiv N})+(n_{H_2}\times B.E_{H-H}) ]-[(n_{NH_3}\times 3\times B.E_{N-H})]$

where,

n = number of moles

Now put all the given values in this expression, we get

$\Delta H=[(1\times 945)+(3\times 432)]-[(2\times 3\times 391)]$

$Delta H=-105kJ$

Therefore, the enthalpy change for this reaction is, -105 kJ

8 0

3 years ago

The noble gases are inert due to the fact that A. their valence shell is empty B. their valence shell is full C. their electrons

coldgirl [10]

Answer:

B) Their valence shell is full

Explanation:

In order to be classified as a noble gas, an element must have a complete octet/ a full shell of valence electrons, as shown in answer B.

A and C are just incorrect. Since noble gasses are very unstable, D is a true statement, but is isn't the correct answer as this does not explain why they are inert.

<h3>Hope this was helpful!</h3>

5 0

3 years ago