How do I proceed to do this? I’m very confused.

Do atoms lend and borrow electrons from inner shells

zaharov [31]

False. They don't borrow electrons at all. They already have their respective electron affinities. This is called as electronegativity, and it's an occurence where it already has its own from its actual structure. It never borrows any electrons at all.

4 0

3 years ago

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch

Salsk061 [2.6K]

Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

2SO2 + O2 ⇄ 2SO3

Initial 3.4 atm 1.3 atm 0 atm

Change -2x - x + 2x

Equilibrium 3.4 - 2x 1.3 -x 0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

2SO2 + O2 ⇄ 2SO3

Equilibrium 3.4 - 0.52 1.3 - 0.26 0.52 atm

Equilibrium 2.88 atm 1.04 atm 0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

$Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135$

8 0

3 years ago

Please help ASAP I’ll make you u as brainlister please 100 points pelaseee

inessss [21]

Answer:

(C) im pretty sure is the answer

Explanation:

6 0

3 years ago

Read 2 more answers

If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?

kvv77 [185]

Answer:

<h2>The answer is 14.29 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have

$P(\%) = \frac{0.1}{0.7} \times 100 \\ = 14.285714...$

We have the final answer as

Hope this helps you

4 0

3 years ago

SO2________________.

Mashcka [7]

Answer:

a. Dipole-dipole bonding

Explanation:

SO2 has dipole-dipole bonding. This is because of the difference in the electronegativities of Sulphur and oxygen. Moreover, the lone pair of electrons on S gives it bent shape with a net dipole unlike CO2 which has a linear shape.( This why CO2 does not have any dipole moment).

So, the correct answer is a.

6 0

3 years ago