Question

Determine the percent water in CuSO4.5 H2O to three significant figures.

Answer 1

Answer:

$\%\;of \;water = 36.08\%$

Explanation:

Molecular mass of $CuSO_4.5H_2O = 249.72\;g/mol$

Molecular mass of $H_2O = 18.02\;g/mol$

In $CuSO_4.5H_2O$, 1 mole of compound has 5 moles of $H_2O$.

Mass of 5 moles of $H_2O = No.\; of\;mole\;of\;water \times\;molecular\;mass\;of\;water$

Mass of 5 moles of $H_2O = 5\times 18.02 = 90.10\;g/mol$

$\%\;of \;water=\frac{Mass\;of\;water}{Tolat\;mass\;of\;CuSO_4}$

$\%\;of \;water = \frac{90.10}{249.72}\times 100= 36.08\%$