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Art [367]
3 years ago
10

The mine car and its contents have a total mass of 6.0 Mg and a center of gravity at G. If the coefficient of static friction be

tween the wheels and the tracks is μs = 0.4 when the wheels are locked, find the normal force acting on the front wheels at B and the rear wheels at A when the brakes at both A and B are locked. Does the car move?

Physics
1 answer:
ohaa [14]3 years ago
3 0

Answer:

The mine car does not move

Explanation:

Attached below is a comprehensive explanation on how I arrived at my answer.

Cheers

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A car from rest moves a distance s(m) in t second, where s=3t³+t²/4 determine(i)the initial acceleration of the car (ii)the acce
Sunny_sXe [5.5K]

Answer:

0.5 , 54.5

Explanation:

for acceleration we should derivate the equation 2 times

x=3t³+t²/4

v=9t²+t/2

a=18t+1/2

a(0)=0.5

a(3)=54.5

8 0
3 years ago
Jorge asked, "Where are the apples?" Which sentence revises the sample sentence to the indicative mood? Where are the apples? Jo
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Answer:

Jorge wanted to know where the apples were

Explanation:

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2 years ago
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Coil the wire around the nail. Connect one end of the wire to the positive battery terminal. Connect the other end of the wire t
Andrej [43]
Static i think 
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5 0
3 years ago
A ball is dropped off a cliff and falls for 24 seconds. How far did the ball fall from the top down
DerKrebs [107]

Answer:

9266 feet

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with Earth's gravity and long it fell that's as good as it gets if there was no other factors like wind mass weight but your welcome

4 0
2 years ago
A student carried out an experiment adding different weights to a spring and recording the results. Look at the table of results
MAXImum [283]

Answer:

0.25 m.

Explanation:

We'll begin by calculating the spring constant of the spring.

From the diagram, we shall used any of the weight with the corresponding extention to determine the spring constant. This is illustrated below:

Force (F) = 0.1 N

Extention (e) = 0.125 m

Spring constant (K) =?

F = Ke

0.1 = K x 0.125

Divide both side by 0.125

K = 0.1/0.125

K = 0.8 N/m

Therefore, the force constant, K of spring is 0.8 N/m

Now, we can obtain the number in gap 1 in the diagram above as follow:

Force (F) = 0.2 N

Spring constant (K) = 0.8 N/m

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F = Ke

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Divide both side by 0.8

e = 0.2/0.8

e = 0.25 m

Therefore, the number that will complete gap 1is 0.25 m.

5 0
3 years ago
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