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Nimfa-mama [501]
3 years ago
6

Which of the following statements are true of solids? A.The particles do not vibrate. B.The particles are in a fixed location. C

.They have strong intermolecular forces between the atoms or molecules. D.The particles have less kinetic energy than those of liquids or gases.
Physics
1 answer:
EastWind [94]3 years ago
8 0

The answer is B.

A. Particles are always vibrating. The hotter the object, the more average kinetic energy the particles have, and thus vibrating faster. If the matter is cooled down to absolute zero (ie. 0K or -273°C), the particles will stop vibrating as they lose all the kinetic energy.

B. Particles in solids are vibrating within a fixed location. They are closely packed together, forming a regular and fixed shape. When the solids are heated up and become liquid or gas, the particles will gain potential energy, which allows them to move around and further apart from each other. Thus, liquid and gas do not have a fixed shape.

C. Intermolecular forces are the chemical bonds (eg. ionic bond, covalent bond) among atoms and molecules. Stronger bonds result in a higher boiling point and melting point as more energy is required to break the forces. Yet, even substances with weak intermolecular forces could still be frozen to solid, so the strength of the bonds does not affect the physical states of the substance.

D. For the same kind of substance, solid has a lower temperature than liquid and gas. Temperature is proportional to the average kinetic energy of the particles, so the particles vibrate less vigorously. Yet, taking water and ice as an example, if you have a large piece of ice and a drop of water, although the average kinetic energy of ice is lower than that of water, the total kinetic energy of the particles in the ice could still be larger than that in the water, since there are many more particles in the ice.

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Please help me with this question​
vovangra [49]

Answer:

1. 12 V

2a. R₁ = 4 Ω

2b. V₁ = 4 V

3a. A = 1.5 A

3b. R₂ = 4 Ω

4. Diagram is not complete

Explanation:

1. Determination of V

Current (I) = 2 A

Resistor (R) = 6 Ω

Voltage (V) =?

V = IR

V = 2 × 6

V = 12 V

2. We'll begin by calculating the equivalent resistance. This can be obtained as follow:

Voltage (V) = 12 V

Current (I) = 1 A

Equivalent resistance (R) =?

V = IR

12 = 1 × R

R = 12 Ω

a. Determination of R₁

Equivalent resistance (R) = 12 Ω

Resistor 2 (R₂) = 8 Ω

Resistor 1 (R₁) =?

R = R₁ + R₂ (series arrangement)

12 = R₁ + 8

Collect like terms

12 – 8 =

4 = R₁

R₁ = 4 Ω

b. Determination of V₁

Current (I) = 1 A

Resistor 1 (R₁) = 4 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 1 × 4

V₁ = 4 V

3a. Determination of the current.

Since the connections are in series arrangement, the same current will flow through each resistor. Thus, the ammeter reading can be obtained as follow:

Resistor 1 (R₁) = 4 Ω

Voltage 1 (V₁) = 6 V

Current (I) =?

V₁ = IR₁

6 = 4 × I

Divide both side by 4

I = 6 / 4

I = 1.5 A

Thus, the ammeter (A) reading is 1.5 A

b. Determination of R₂

We'll begin by calculating the voltage cross R₂. This can be obtained as follow:

Total voltage (V) = 12 V

Voltage 1 (V₁) = 6 V

Voltage 2 (V₂) =?

V = V₁ + V₂ (series arrangement)

12 = 6 + V₂

Collect like terms

12 – 6 = V₂

6 = V₂

V₂ = 6 V

Finally, we shall determine R₂. This can be obtained as follow:

Voltage 2 (V₂) = 6 V

Current (I) = 1.5 A

Resistor 2 (R₂) =?

V₂ = IR₂

6 = 1.5 × R₂

Divide both side by 1.5

R₂ = 6 / 1.5

R₂ = 4 Ω

4. The diagram is not complete

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Explanation:

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However, in most cases, it is a threat to the environment and living beings because storing and managing the wastes of this type of power is difficult and expensive. Indeed, dealing with the wastes of nuclear power requires complex infrastructure, and any accident or leaking leads to serious consequences from the death of those exposed to the wastes to permanent loss of diversity or changes in nearby areas.

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