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lys-0071 [83]
4 years ago
15

a 10.0 kg ball falling at 10.0 m/s hits a mattress and comes to a complete stop in 1 s. what force does the mattress exert to st

op the ball
Physics
1 answer:
eimsori [14]4 years ago
3 0
Using Newton's second law;

F = ma, where m = mass, a = acceleration or deceleration

a = Δv/t = (v-u)/t, but v= 0, u = 10 m/s, t = 1.
Then,
a = (0-10)1 = -10 m/s^2

Substituting;
F = ma = 10*-10 = -100 N

The  mattress exerts 100 N to stop the ball.
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To analyze the experiment used to determine the properties of an electron. In 1909, Robert Millikan performed an experiment invo
sweet-ann [11.9K]

Answer:

C has 5 electrons

Explanation:

Given:

The data acquired from the experiment performed by Millikan:

Q_a = 3.20 x10^{-19}  C

Q_b = 4.80 x10^{-19}  C

Q_c = 8.00 x 10^{-19}  C

Q_d = 9.60 x 10^{-19}  C

Find:

How many Electrons were present in drop C

Solution:

It is known that the charge of an electron e = 1.602 *10^-19 C / electron.

Hence the number of electrons n in drop C will be:

      n = Q_c / e

      n = 8.00 x 10^{-19}  / 1.602*10^-19

      n = 4.99 = 5 electrons  

Answer: The drop C contains 5 electrons.

5 0
3 years ago
Consider an NACA 2412 airfoil with a 2-m chord in an airstream with a velocity of 50 m/s at standard sea level conditions. If th
Akimi4 [234]

Answer:

4°

Explanation:

Given,

chord in the airstream, c = 2 m

speed, v = 50 m/s

lift per unit span = 1353 N/m

density of air, ρ = 1.225 kg/m³

Lift,L = c_L \times \dfrac{1}{2} \rho v^2(c \times s)

\dfrac{L}{s}=c_L \times \dfrac{1}{2} \rho v^2\times c

50=c_L \times 0.5\times 1.225\times 50^2\times 2

c_L = 0.44

From the plot of c_L and angle of attack

Angle of attack is equal to 4°

8 0
3 years ago
12. An electric motor is plugged into a standard wall socket and is run- ning at normal speed. Suddenly, some dirt prevents the
rusak2 [61]

the answer would be B. the back emf increases, and the current drawn from the socket increases

more current is needed to make the motor move, like when you try to self crank a motor and the back wires are touching its harder to crank. and the emf increases since more current is being drawn in, strengthening the emf or increasing the emf

8 0
3 years ago
What is the amount of work required to increase a 1100 kg car's speed from 20.0 m/s to 50.0 m/s?
Alchen [17]
La policía de los estados miembros se ha convertido de
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3 years ago
The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C).1.75 J/(g⋅°C). How much heat energy is needed to raise the t
Murljashka [212]

Answer:

Heat energy required = 687.96 kJ

Explanation:

Heat energy required, H = mCΔT.

Mass of cooking oil, m = 2.34 kg = 2340 g

Specific heat of cooking oil, C = 1.75 J/(g⋅°C)

Initial temperature = 23 °C

Final temperature = 191 °C

Change in temperature, ΔT = 191 - 23 = 168 °C

Substituting values

            H = mCΔT

            H = 2340 x 1.75 x 168 = 687960 J = 687.96 kJ

Heat energy required = 687.96 kJ

7 0
3 years ago
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