It would depend on the directions of the boxes, but I believe there would be 3 units of work.
M = mass of the girl = 50 kg
m = mass of skate = 10 kg
V' = initial velocity of girl and skate together before the girl jump = 2 m/s
V = velocity of girl after the jump relative to ground = 3 m/s
v = velocity of the skate after girl jumps = ?
using conservation of momentum
(M + m) V' = MV + m v
inserting the values in the above equation
(50 + 10) (2) = (50) (3) + 10 v
v = - 3 m/s
0
Explanation:
A wall on which an amount of force is acted upon and does not move suggests that no work has been done on the wall.
Work done is the force applied on a body to move it through a particular distance in the direction of the force.
For work to be done:
- Force must be applied to a body or on it
- Distance must be moved in the direction of the applied force
Work done = force x distance moved.
Given parameters:
force = 20N
distance = 0
Work done = 20 x 0 = 0J
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Work done brainly.com/question/9100769
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When forces are balanced, the net force is zero. Their effect
is the same as if there were no forces present at all.
Answer:
t=2.10 s
u= 47.40 m/s
Explanation:
given that
h= 21.8 m
x= 101 m
g=9.8 m/s²
Lets take horizontal speed of ball = u m/s
The vertical speed of the car at initial condition is zero ( v= 0).
We know that
v= 0 m/s
now by putting the values
21.8 = 1/2 x 9.8 x t²
t=2.10 s
This is time when ball was in motion.
Now in horizontal direction
x = u .t
101 = u x 2.1
u= 47.40 m/s