Answer:
a) A = 0.603 m
, b) a = 165.8 m / s²
, c) F = 331.7 N
Explanation:
For this exercise we use the law of conservation of energy
Starting point before touching the spring
Em₀ = K = ½ m v²
End Point with fully compressed spring
=
= ½ k x²
Emo = 
½ m v² = ½ k x²
x = √(m / k) v
x = √ (2.00 / 550) 10.0
x = 0.603 m
This is the maximum compression corresponding to the range of motion
A = 0.603 m
b) Let's write Newton's second law at the point of maximum compression
F = m a
k x = ma
a = k / m x
a = 550 / 2.00 0.603
a = 165.8 m / s²
With direction to the right (positive)
c) The value of the elastic force, let's calculate
F = k x
F = 550 0.603
F = 331.65 N
Answer:
q2 = - 8 ×
C
negative sign because attract together
Explanation:
given data
q1 = +3.2 µC = 3.2 ×
C
distance r = 0.28 m
force F = 2.9 N
to find out
q2 (magnitude and sign)
solution
we know that here if 2 charge is unlike charge
than there will be electrostatic force of attraction , between them
now we apply coulomb law that is
F =
............1
here we know
= 9 ×
Nm²/C²
so from equation 1
2.9 = 9 ×
×
q2 = 
q2 = - 8 ×
C
Answer:
canola oil biome is a chemically refined oil that is used for cooking and skin
Explanation:
Answer:
Explanation:
The energy and the frequency of electromagnetic radiation inversely proportional to the frequency of radiation.
So, as the wavelength increases, the energy and the frequency decreases.