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AysviL [449]
4 years ago
5

A 2-ft-diameter hemispherical plexiglass "bubble" is to be used as a special window on the side of an above-ground swimming pool

. The window is to be bolted onto the vertical wall of the pool and faces outward, covering a 2-ft-diameter opening in the wall. The center of the opening is 5.9 ft below the surface. Determine the (a) horizontal and (b) vertical components of the force of the water on the hemisphere.

Physics
1 answer:
Taya2010 [7]4 years ago
6 0

Answer:

a) 1156.8 lb

b) 130.7 lb

Explanation:

See attachment

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Assuming no air resistance, all projectiles have:
Kitty [74]

Answer: Option C

C) accelerated vertical motion and constant horizontal motion.

Explanation:

If there is no air resistance then during the projectile movement the only force that causes an acceleration is the gravitational force.

We know that this force produces an acceleration of 9.8 m / s ^ 2 in the projectile.

As the gravitational force attracts the object towards the earth, then the acceleration that this force produces is always in the vertical direction. In the horizontal direction the object is not accelerated (because there is no air resistance).

Therefore the correct answer is option C.

 "accelerated vertical motion and constant horizontal motion".

3 0
3 years ago
What is the impact force on a 0.5 kg object if it falls 3 meters and hits a carpeted floor at 8 m/s, stopping in 0.10 seconds?
Cerrena [4.2K]

the I'm pact force of 0.5 is lol u guys go and study why r u asking answers

4 0
3 years ago
A car of mass 875 kg is traveling 30.0 m/s when the driver applies the brakes, which lock the wheels. The car skids for 5.60 s i
AleksAgata [21]

Explanation:

It is given that,

Mass of the car, m = 875 kg

Initial speed of the car, u = 30 m/s

Brakes are applied i.e. v = 0

The car skids for 5.60 s in the positive x - direction before coming to rest, t = 5.6

(a) Acceleration of the car, a=\dfrac{v-u}{t}

a=\dfrac{0-30}{5.6}

a=-5.35\ m/s^2

(b) Force, F = ma

F=875\ kg\times -5.35\ m/s^2

F = -4681.25 N

So, the force of 4681.25 N is acting on the car.

(c) Let x is the distance covered by the car. So,

v^2-u^2=2ax

0-u^2=2ax

x=\dfrac{-u^2}{2a}

x=\dfrac{-(30\ m/s)^2}{2\times -5.35\ m/s^2}

x = 84.11 meters

So, the distance covered by the car is 84.11 meters. Hence, this is the required solution.

7 0
3 years ago
What is the difference between gross anatomy and microscopic anatomy?
Maurinko [17]
There are two major types of anatomy. Gross (macroscopic) anatomy is the study of anatomical structures that can be seen by the eye, such as the external and internal bodily organs. Microscopic anatomy is the study of tiny anatomical structures such as tissues and cells.
5 0
3 years ago
Read 2 more answers
A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a spe
Rasek [7]

Answer:

56.5\ \text{s}

21.13\ \text{m/s}

Explanation:

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

s = Displacement

Here the kinematic equations of motion are used

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{25-0}{2}\\\Rightarrow t=12.5\ \text{s}

Time the car is at constant velocity is 39 s

Time the car is decelerating is 5 s

Total time the car is in motion is 12.5+39+5=56.5\ \text{s}

Distance traveled

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{25^2-0}{2\times 2}\\\Rightarrow s=156.25\ \text{m}

s=vt\\\Rightarrow s=25\times 39\\\Rightarrow s=975\ \text{m}

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{5}\\\Rightarrow a=-5\ \text{m/s}^2

s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-25^2}{2\times -5}\\\Rightarrow s=62.5\ \text{m}

The total displacement of the car is 156.25+975+62.5=1193.75\ \text{m}

Average velocity is given by

\dfrac{\text{Total displacement}}{\text{Total time}}=\dfrac{1193.75}{56.5}=21.13\ \text{m/s}

The average velocity of the car is 21.13\ \text{m/s}.

6 0
3 years ago
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