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MAVERICK [17]
3 years ago
14

3. A laser with a wavelength of 650 nm passes through a double slit. A pattern is observed on a wall that is 1.5 meters away fro

m the slits. The spacing between 10 bright fringes is measured to be 3 cm. Calculate the separation between the slits. Show your work.
Physics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

Slit separation, d=3.25\times 10^{-4}\ m

Explanation:

It is given that,

Wavelength of laser light, \lambda=650\ nm=650\times 10^{-9}\ m

Distance between pattern and the wall, L = 1.5 m

The spacing between 10 bright fringes is, y = 3 cm = 0.03 m

We need to find the separation between the slits. According to the equation of diffraction law :

d\ sin\theta=n\lambda

Where

d is the separation between the slits

For smaller angles, sin\theta=tan\theta=\dfrac{y}{L}

d(\dfrac{y}{L})=n\lambda

d=\dfrac{n\lambda L}{y}

d=\dfrac{10\times 650\times 10^{-9}\times 1.5}{0.03}

d = 0.000325 m

or

d=3.25\times 10^{-4}\ m

So, the separation between the slits is 3.25\times 10^{-4}\ m. Hence, this is the required solution.

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ale4655 [162]

Answer:

140265.8 C = 1.403 × 10⁵ C

Explanation:

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K.E = (1/2)(757)(25²) = 236562.5 J

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And this would be equal to the potential of the battery.

For the battery, potential difference = (electric potential energy)/(charges moved)

ΔV = ΔU/q

q = ΔU/ΔV

ΔU = 1683189.5 J

ΔV = 12.0 V

q = 1683189.5/12 = 140265.8 C

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A 4kg book sits on a table and your pet hamster puts his front paws on the book and pushes down with a force of 3N. What is the
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There are three forces acting on the book. 
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Since the book is not moving, the net force is zero. The summation of all forces must be zero. Then we could find the normal force which is unknown (denoted as x).

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Therefore, the normal force is 42 N.
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If an automobile engine delivers a power of 50.0 hp, how much time will it take for the engine to do 6.40 x 10^4 j of work? (1 h
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Given data

Power (P) = 50 hp,

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                = 37300 Watts      (Watt = J/s)  

Work  = 6.40 ×10⁴ J

Power is defined as rate of doing work and the unit of power is<em> Watt.</em>

Mathematically,

         Power = (Work / time)   Watts

                     = 6.40 ×10⁴ / time

          37300 W = 6.40 ×10⁴ J /time      (Where time in seconds)

         => time = Work/Power

                      = 6.40 ×10⁴/37300

                      = <em>1.74 seconds  </em>

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<em> </em>


7 0
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Answer:

(a) nearsighted

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(c) the absolute value of the focal length (f) is given by the formula:

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So it would normally be written with a negative signs in front indicating a divergent lens.

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