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MAVERICK [17]
3 years ago
14

3. A laser with a wavelength of 650 nm passes through a double slit. A pattern is observed on a wall that is 1.5 meters away fro

m the slits. The spacing between 10 bright fringes is measured to be 3 cm. Calculate the separation between the slits. Show your work.
Physics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

Slit separation, d=3.25\times 10^{-4}\ m

Explanation:

It is given that,

Wavelength of laser light, \lambda=650\ nm=650\times 10^{-9}\ m

Distance between pattern and the wall, L = 1.5 m

The spacing between 10 bright fringes is, y = 3 cm = 0.03 m

We need to find the separation between the slits. According to the equation of diffraction law :

d\ sin\theta=n\lambda

Where

d is the separation between the slits

For smaller angles, sin\theta=tan\theta=\dfrac{y}{L}

d(\dfrac{y}{L})=n\lambda

d=\dfrac{n\lambda L}{y}

d=\dfrac{10\times 650\times 10^{-9}\times 1.5}{0.03}

d = 0.000325 m

or

d=3.25\times 10^{-4}\ m

So, the separation between the slits is 3.25\times 10^{-4}\ m. Hence, this is the required solution.

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Answer:

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Explanation:

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  v = √(k/m)   x

  v = √ (3/8.00)   0.15

  v = 0.09186 = 9.18 10⁻² m/s

This is the spped of  the  block  plus bullet rsystem right after the crash

We substitute calculate in equation  (1)

   m v₀ = (m + M) v

  v₀ = v (m + M) / m

  v₀ = 0.09186 (0.008 + 0.992) /0.008

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Two slits in an opaque barrier each have a width of 0.020 mm and are separated by 0.050 mm. When coherent monochromatic light pa
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Answer:

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