Answer:
block velocity v = 0.09186 = 9.18 10⁻² m/s and speed bollet v₀ = 11.5 m / s
Explanation:
We will solve this problem using the concepts of the moment, let's try a system formed by the two bodies, the bullet and the block; In this system all scaffolds during the crash are internal, consequently, the moment is preserved.
Let's write the moment in two moments before the crash and after the crash, let's call the mass of the bullet (m) and the mass of the Block (M)
Before the crash
p₀ = m v₀ + 0
After the crash
= (m + M) v
p₀ = 
m v₀ = (m + M) v (1)
Now let's lock after the two bodies are joined, in this case the mechanical energy is conserved, write it in two moments after the crash and when you have the maximum compression of the spring
Initial
Em₀ = K = ½ m v2
Final
E
= Ke = ½ k x2
Emo = E
½ m v² = ½ k x²
v² = k/m x²
Let's look for the spring constant (k), with Hook's law
F = -k x
k = -F / x
k = - 0.75 / -0.25
k = 3 N / m
Let's calculate the speed
v = √(k/m) x
v = √ (3/8.00) 0.15
v = 0.09186 = 9.18 10⁻² m/s
This is the spped of the block plus bullet rsystem right after the crash
We substitute calculate in equation (1)
m v₀ = (m + M) v
v₀ = v (m + M) / m
v₀ = 0.09186 (0.008 + 0.992) /0.008
v₀ = 11.5 m / s
Answer:
multiply that and divided by 45
Answer:
Amplitude : The height of the wave from the origin to the crest/peak or trough
Explanation:
Answer:
p = 1.0076 10⁵ Pa
Explanation:
Atmospheric pressure is given by the relation
P = rho g h
In this case they indicate that the height of the column of mercury is h = 756 mm Hg
let's reduce the height to the SI system
h = 756 mm (1m / 1000 mm)
h = 0.756 m
let's calculate
P = 13600 9.8 0.756
p = 1.0076 10⁵ Pa
Answer:
The answer is 5
Explanation:
The maximum interference is:
m * λ = d * sinθi
Where m = 0,1,2,3,...
The first minimum diffraction is:
λ = a * sinθd
|sinθi| < sinθd
Where
(|m| * λ)/d < λ/a
|m| < d/a = 2.5
|m|max = 2
It can be concluded that coherent monochromatic light passes through the slits, therefore the maximum number of interference is 5.