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Sophie [7]
3 years ago
11

Describe the capillary action in acetone compared to water

Chemistry
2 answers:
lakkis [162]3 years ago
6 0
Capillary action is defined as the ability of a liquid to go up a narrow space without the help or opposition of external forces. One of the most important factors affecting capillary action is the intermolecular forces within a substance. The higher the IMF, the greater the capillary action. The H-bonding in water gives it greater IMF than acetone, so water has greater capillary action.
cricket20 [7]3 years ago
3 0
Liquid going up a thin space without the assistance off an opposite or opposing force
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4 years ago
Read 2 more answers
9.The industrial preparation of hydrogen gas from water gas is referred to as​
natima [27]

Answer: Bosch process

Explanation:

Bosch process is an industrial process for the manufacture of H2. This proces uses cheap raw materials( water and coke) to generate water gas which is mixed with water in the presence of a catalyst(iron(II) oxide or chromium(iii) oxide) to generate H2

6 0
4 years ago
What is the density of a copper blocks if it has a mass of 43.5 grams and a volume of 4.85 cm^3?
Marianna [84]
8.97 g/cm^

D=m/v
D=43.5/4.85cm^3
D=8.97 g/cm^3
7 0
3 years ago
Calculate either [H3O+] or [OH−] for each of the solutions at 25 °C. Solution A: [OH−]=1.55×10−7 M Solution A: [H3O+]= M Solutio
Ahat [919]

Answer: A. [H_3O^+]=0.64\times 10^{-7}M

B. [OH^-]=0.11\times 10^{-5}M

C. [OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M

Thus solution B is basic in nature.

Explanation:

pH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH for acidic solutions is less than 7, for basic solutions it is more than 7 and for neutral solutions it is equal to 7.

pH=-\log [H^+]

pOH=-log[OH^-]

pH+pOH=14

or [H^+][OH^-]=10^{-14}

A. [OH^-]=1.55\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{1.55\times 10^{-7}}=0.64\times 10^{-7}M

pH=-log[H_3O^+]=-log[0.64\times 10^{-7}]=7

B. [H_3O^+]=9.43\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.43\times 10^{-9}}=0.11\times 10^{-5}M

pH=-log[H_3O^+]=-log[9.43\times 10^{-9}]=8

C. [H_3O^+]=0.000775M

[OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M

pH=-log[H_3O^+]=-log[0.000775]=3

Thus solution B is basic.

4 0
3 years ago
Two students pull a box with force of 100 N to the left and 200 N to the right.
laiz [17]

Answer:

net force is 100 N and direction is right

Explanation:

7 0
3 years ago
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