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a_sh-v [17]
4 years ago
7

-2(-x+1)+3x+3=26 how solve it

Mathematics
1 answer:
timama [110]4 years ago
8 0
Combine like terms then solve as a one step equation
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Forty-four students go on a field trip. The students are divided into groups of 7 students. How many groups of 7 will there be?.
strojnjashka [21]

6

To solve this problem, you need to divide the total number of students going on the field trips with the number of students in each group.

44/7

= 6 R 2

Since, I assume there can <em>only</em> be groups of 7, the answer is 6.

4 0
3 years ago
Liam uses 2 quarts of yellow paint and adds 3 1/4 Jars of blue paint.Evan uses 1/2 quarts of yellow paint and adds 5 1/2 of red
EleoNora [17]

Answer:

2 + (13/4)x = 1/2 + (11/2)y

Step-by-step explanation:

Let each jar of paint used by Liam be x

Let each jar of paint used by Evan be y.

Liam uses 2 quarts of yellow paints and adds 3 1/4 jars of blue paint. so we have

2 + 3 1/4x

= 2 + (13/4)x

Since Evan also uses 1/2 quarts of yellow paints and add 5 1/2 jar of red paint, we have

1/2 + 5 1/2y

= 1/2 + (11/2)y

Since they end up with the same volume of paint, we have

2 + (13/4)x = 1/2 + (11/2)y

7 0
3 years ago
How many ways can you write 5^8 as a quotient of two exponential terms? Explain your reasoning.
melisa1 [442]
Exponents can be expressed in terms of quotient or fraction.
For example: x^6 can be expressed as x^8 / x^2 = x^8-2 = x^6.

From the question, 5^8 can be expressed as 
5^10/5^2 = 5^8
(5^2)(5^8) / (5^2) = 5^8
6 0
4 years ago
Find the perimeter and area of the rectangle.<br> 6.9 in<br> 2.4 in
saveliy_v [14]

Answer:The perimeter = 18.6 , The area= 16.56

Step-by-step explanation: The perimeter is all sides added together and there are four sides and two sides are even , so there are two ways to find it. {1} 6.9x2=13.8 , 2.4x2=4.8; 13.8+4.8=18.6…{2} 6.9+6.9+2.4+2.4=18.6.

The area is two sides multiplied together so, 6.9x2.4=16.56

7 0
3 years ago
If someone have all the proofs of this I’ve been trying since yesterday PLEASE
lord [1]

Answer:

Please see steps below

Step-by-step explanation:

Notice the following:

(a) Angles 5 and 1 are alternate angles between parallel lines, and then they must be congruent (equal in measure)  \angle 1 \,=\,\angle 5

(b) Angles 6 and 3 are also alternate angles  between parallel lines, so they must be congruent (equal measure)  \angle 3 \,=\,\angle 6

Therefore, instead of expressing the addition:

\angle 5\,\,+\,\,\angle 2\,\,+\,\,\angle 6

we can write:

\angle 1\,\,+\,\,\angle 2\,\,+\,\,\angle 3

which in fact clearly add to 180^o

8 0
3 years ago
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