Question

cheAt an amusement park, a swimmer uses a water slide to enter the main pool. If the swimmer starts at rest, slides without friction, and falls through a vertical height of 2.77 m, what is her speed at the bottom of the slide

Answer 1

Answer:

$v \approx 7.371\,\frac{m}{s}$

Explanation:

The swimmer can be modelled by the Principle of Energy Conservation. The speed is derived herein:

$m_{swimmer}\cdot g \cdot h = \frac{1}{2}\cdot m_{swimmer}\cdot v^{2}$

$v = \sqrt{2\cdot g \cdot h}$

$v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (2.77\,m)}$

$v \approx 7.371\,\frac{m}{s}$